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A string fixed at both the ends forms st...

A string fixed at both the ends forms standing waves with node separation of 5 cm. If the velocity of waves travelling in the string is 4 m/s, then the frequency of vibration of the string will be

A

20 Hz

B

30 Hz

C

40 Hz

D

50 Hz

Text Solution

Verified by Experts

The correct Answer is:
C
`lambda/2 = 5 :. lambda = 10 cm . :. n = v/lambda = 4/(0.1) = 40 ` Hz
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Knowledge Check

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