If 224 mL of a triatomic has has a mass of 1 g at 273K and I atmoshphere pressure then the mass of one atom is

Options

A. `8.30xx10^(-23)`
B. `2.08xx10^(-23)`
C. `5.53xx10^(-23)`
D. `6.24xx10^(-23)`

Answer

C

Explanation

The conditions given are standard conditions
224 mL has mass = 1g
22400 mL will have mass = 100 g this is mol .wt of gas `6.023 xx10 ^(23) ` molecules have `3xx6.023 xx10^(23) `atoms
`therefore ` weight of one atom
`=( 100)/( 3xx6.023xx10^(23) )=5.5xx10^(-23) g`