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If 224 mL of a triatomic has has a mass ...

If 224 mL of a triatomic has has a mass of 1 g at 273K and I atmoshphere pressure then the mass of one atom is

A

`8.30xx10^(-23)`

B

`2.08xx10^(-23)`

C

`5.53xx10^(-23)`

D

`6.24xx10^(-23)`

Text Solution

Verified by Experts

The correct Answer is:
C

The conditions given are standard conditions
224 mL has mass = 1g
22400 mL will have mass = 100 g this is mol .wt of gas `6.023 xx10 ^(23) ` molecules have `3xx6.023 xx10^(23) `atoms
`therefore ` weight of one atom
`=( 100)/( 3xx6.023xx10^(23) )=5.5xx10^(-23) g`
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Knowledge Check

  • If 224 ml of a triatomic gas has a mass of 1 gm at 273 K and 1 atmospheric pressure then the mass of one atom is

    A
    `8.30xx10^(-23)gm`
    B
    `2.08xx10^(-23)gm`
    C
    `5.53xx10^(-23)gm`
    D
    `6.24 xx10^(-23)gm`
  • If 224 mL of triatomic gas has a mass of 1 g at 273 K and 1 atm. Pressure, then the mass of one atom is

    A
    `8.30xx10^(-23)`g
    B
    `6.24xx10^(-23)`g
    C
    `2.08xx10^(-23)`g
    D
    `5.54xx10^(-23)`g
  • 224 mL of a triatomic gas weights 1 g at 273K and 1 atm . The mass of one atom of this gas is:

    A
    `8.30xx10^(-23) g`
    B
    `2.08xx10^(-23)g`
    C
    `5.53xx10^(-23)g`
    D
    `6.24xx10^(-23)g`
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