The hybridization of atomic orbitals of nitrogen in `NO_(2)^(+),NO_(2)^(-) and NH_(4)^(+)` arc

Options

A. `sp^(2),sp^(3) and sp^(2)` respectively
B. `sp,sp^(2) and sp^(3)` respectively
C. `sp^(2),sp and sp^(3)` respectively
D. `sp^(2),sp^(3) and sp` respectively

Answer

B

Explanation

`NO_(2)^(+)=(1)/(2)[5+0+0-1]=2sp,NO_(2)^(-)=(1)/(2)[5+0+1-0]`
`=3sp^(2),NH_(4)^(+)=(1)/(2)[5+4+0-1]=4sp^(3)`