Home
Class 12
PHYSICS
A proton of mass m and charge q is accel...

A proton of mass m and charge q is accelerated by a potential difference V in a perpendicular magnetic field B occupying space t. The value of `sin theta` where `theta` is deviation of proton from initial direction is

A

`Bt sqrt((q)/(3 Vm))`

B

`Bt sqrt((q)/(2 Vm))`

C

`Bt sqrt((2q)/(Vm))`

D

`Bt sqrt((q)/(Vm))`

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MAGNETIC EFFECT OF ELECTRIC CURRENT

    TARGET PUBLICATION|Exercise COMPETITIVE THINKING|111 Videos

  • KINETIC THEORY OF GASES AND RADIATION

    TARGET PUBLICATION|Exercise Evaluation test|18 Videos

  • MAGNETISM

    TARGET PUBLICATION|Exercise EVALUATION TEST|14 Videos

Similar Questions

Explore conceptually related problems

A particle of mass m and charge q is accelerated by a potential difference V volt and made to enter a magnetic field region at an angle theta with the field. At the same moment, another particle of same mass and charge is projected in the direction of the field from the same point. Magnetic field induction is B. What would be the speed of second particle so that both particles meet again and again after regular interval of time. Also, find the time interval after which they meet and the distance travelled by the second particle during that interval.

A charge particle of mass m and charge q is accelerated by a potential difference V volt. It enters in a region of uniform magnetic field Bas shown in figure-4.93. Find the time after which it will come out from the magnetic field.

Knowledge Check

  • A particle of mass 'm' and charge 'q' is accelerated through a potential difference of V volt, its energy will be

    A
    `qV`
    B
    `mqV`
    C
    `((q)/(m))V`
    D
    `(q)/(mV)`

  • A particle of mass .m. and charge .q. is accelerated through a potential difference of .V. volt. Its energy is

    A
    qV
    B
    mqV
    C
    `((q)/(m))V`
    D
    `(q)/(mV)`

  • A particle of mass m carrying charge q is accelerated by a potential difference V. It enters perpendicularly in a region of uniform magnetic field B and executes circular arc of radius R, then q/m equals

    A
    `(2V)/(B^(2)R^(2))`
    B
    `V/(2BR)`
    C
    `(VB)/(2R)`
    D
    `(mV)/(BR)`

    • Similar Questions

    Explore conceptually related problems

    A charged particle having mass m and charge q is accelerated by a potential difference V, it flies through a uniform transverse magnetic field B. The field occupies a region of space d. Fnd the time interval for which it remains inside the magnetic field.

    (a) A charged particle having mass m and charge q is accelerated by a potential difference V , it flies through a uniform transverse magnetic field B . The field occupies a region of space d . Find the time interval for which it remains inside the magnetic field. (b) An alpha -particle is acceleration by a potential difference of 10^(4) V . Find the change in its direction of motion if it enters normally in a region of thickness 0.1 m having transverse magnetic induction of 0.1 T . (m_(alpha) = 6.4 xx 10^(-27) kg) . ( c) A 10 g bullet having a charge of 4 muC is fired at speed of 270 m//sec in a horizontal direction. A vertical magnetic field of 500 muT exists in the space. Find the deflection of the bullet due to the magnetic field as it travels through 100 m . Make appropriate approximations.

    If a proton, deuteron, and alpha particle on being accelerated by the same potential difference enters perpendicular to the magnetic field, then the ratio of their kinetic energies is

    A charged particle of mass m and charge q is accelerated through a potential difference of V volts. It enters a region of uniform magnetic field which is directed perpendicular to the direction of motion of the particle. Find the radius of circular path moved by the particle in magnetic field.

    A charged particle of mass m and charge q is accelerated through a potential differences of V volts. It enters of uniform magnetic field B which is directed perpendicular to the direction of motion of the particle. The particle will move on a circular path of radius

    Home
    Profile