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The minimum kinetic energy of a ground s...

The minimum kinetic energy of a ground state hydrogen atom required to have head-on collision with another ground state hydrogen atom but at rest to produce a photon is given by

A

4.20 eV

B

20.4 eV

C

2.04 eV

D

`-9.1 eV`

Text Solution

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The correct Answer is:
B
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At what minimum kinetic energy must a hydrogen atom move for it's inelastic headon collision with another stationary hydrogen atom so that one of them emits a photon? Both atoms are supposed to be in the ground state prior to the collision.

Energy in the ground state of hydrogen atom is -13.6 eV. What is the energy in the first excited state ?

Knowledge Check

  • Assuming that the mass of proton is nearly equal to mass of neutron the minimum kinetic energy in 10^(1) eV of a neutron for inelastic head on collision with a ground state hydrogen atom at rest is -

    A
    4
    B
    2
    C
    6
    D
    8

  • The minimum enegry required to excite a hydrogen atom from its ground state is

    A
    `13.6 eV`
    B
    `-13.6 eV`
    C
    `3.4 eV`
    D
    `10.2 eV`

  • The energy required to excite an electron from the ground state of hydrogen atom to the first excited state, is

    A
    `1.602 xx 10^(-14) J`
    B
    `1.619 xx 10^(-16) J`
    C
    `1.632 xx 10^(-18) J`
    D
    `1.656 xx 10^(-20) J`

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    Calculate the energy of the electron in the ground state of the hydrogen atom.

    The kinetic energy of an electron in hydrogen atom is 3.40 eV .The minimum energy required to ionise the hydrogen atom is

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    If the potential energy is taken zero at ground state of hydrogen atom in place of infinity then

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