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In an experiment the two slits are 0.5mm...

In an experiment the two slits are `0.5mm`apart and the fringes are observed to`100cm`from the plane of theslits ,The distance of the`11th`bright fringe from the ist bright fringe is `9.72mm`.calcualte the wavelength

A

`4.85xx10^(-5)cm`

B

`4.85xx10^(-5)m`

C

`4.86xx10^(-7)cm`

D

`4.86xx10^(-5)cm`

Text Solution

Verified by Experts

Given `d=.5mm =5xx10^(-2)cm,`
`X_(n)=X_(11)-X_(1)=9.72mm`
`:.X_(n)=(nlambdaD)/(d) n=11-1=10`
`rArr lambda=(X_(n)D)/(d) =(.972xx5xx10^(-2))/(10xx100) rArr lambda=4.86xx10^(-5)cm`
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Knowledge Check

  • The distance of n^(th) bright fringe from the centre of the interference pattern is

    A
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    `x_(n)=Dn`
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