Home
Class 11
CHEMISTRY
The second period (n = 2) involves the f...

The second period `(n = 2)` involves the filling up to electron in__________atomic orbitals.

A

two

B

three

C

four

D

five

Text Solution

Verified by Experts

The correct Answer is:
C
The orbitals being gilled are `2s, 2p_(x),2p_(y)`, and `2p_(z)`.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN ELEMENTS

    R SHARMA|Exercise Follow-up Test 2|1 Videos

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN ELEMENTS

    R SHARMA|Exercise Follow-up Test 3|1 Videos

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN ELEMENTS

    R SHARMA|Exercise Follow-up Test 1|1 Videos

  • CHEMICAL BONDING

    R SHARMA|Exercise Archives|73 Videos

  • EQUILIBRIUM

    R SHARMA|Exercise ARCHIVES|69 Videos

Similar Questions

Explore conceptually related problems

If the velocity of the revolving electron of He^(+) in the first orbit (n= 1) is v. the velocity of the electron in the second orbit is:

What is the value of n for which time period is 8 times the time period of electron is first orbit of hydrogen atom ?

Knowledge Check

  • The third period ( n = 3) involves the filling up to electrons in_______elements.

    A
    `8`
    B
    `18`
    C
    `27`
    D
    `10`

  • The fourth period (n = 4) does not involve the filling up of electrons in_______subshell. (i) 4s (ii) 4p (iii) 4d (iv) 4f

    A
    `(iii)`
    B
    `(iv)`
    C
    `(iii),(iv)`
    D
    `(ii),(iii),(iv)`

  • Which of the following statements are correct ? (i) The seond period (n=2) starts with lithium and third electron enters the 2s orbital. The next element, beryllium has four electrons and has the electronic configuration 1s^(2)2s^(2) . From the next element boron, the 2p orbitals are filled with electrons when the L shell is completed at neon (2s^(2)2p^(6)) . Thus there are 8 elements in the second period. (ii) Successive filling of 3s and 3p orbitals gives rise to the third period of 8 elements from sodium to argon. (iii) The fourth period (n=4) starts at potassium and the added electron fill up the first 4s and 4p orbitals than 3d orbitial is filled. (iv) Fifth period begins with rubidium with the filling of 5s orbital and ends at xenon with the filling up of the 5p orbital.

    A
    I and ii
    B
    I, ii and iii
    C
    iii and iv
    D
    I, ii and iv

    • Similar Questions

    Explore conceptually related problems

    The order of filling of electrons in the orbitals of an atom will be

    Assertion: Sixth period is the longest period in the periodic table. Reason : Sixth period involves the filling of all the orbitals of the sixth energy level.

    In Bohr's model of the hydrogen atom the ratio between the period of revolution of an electron in the orbit of n=1 to the period of the revolution of the electron in the orbit n=2 is :-

    In Bohrs model of the hydrogen atom the ratio between the period of revolution of an electron in the orbit n=1 to the period of revolution of the electron in the orbit n=2 is

    Aufbau principle does not give the correct arrangement of filling up of the atomic orbitals in

    Home
    Profile