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The energy of sigma(2x), is greater than...

The energy of `sigma_(2x)`, is greater than that of `sigma_(1s)^**` orbital because

A

`sigma_(2s)` orbital is formed only after `1s`

B

`sigma_(2s)` orbital is bigger than `sigma_(1s)` orbital

C

`sigma_(2s)` orbital has a greater value of `n` than `sigma_(1s)^**`

D

`sigma_(2s)` is a bonding orbital while `sigma_(2x)^**` is an antibonding orbital.

Text Solution

Verified by Experts

The correct Answer is:
C

Although the antibonding orbital `(sigma_(1s)^**)` has higher energy and is, thus, less stable than the bonding orbitals `(sigma_(1s))`, but this antibonding orbital has greater stability than the bonding orbital `(sigma_(2s))` because the energy of an MO increases as the value of the principal quantum number `(n)` increases.
This simply reminds us that the concepts of stability and energy applied here are relative.
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Assertion: The first ionization energy of Be is greater than that of B. Reason: 2p-orbital is lowerr in energy than 2s-orbital.

Assertion: The first ionization energy of Be is greater than that of B. Reason: 2p-orbital is lower in energy than 2s-orbital.

Knowledge Check

  • The energy of sigma2s -orbital is greater than sigma^("*")1s orbital because

    A
    `sigma2s` orbital is bigger than als orbitat
    B
    `sigma2s` orbital is a bonding orbital whereas, `sigma^("*")1s` is an antibonding orbital
    C
    `sigma2s` orbital has a greater value of n than `sigma^("*")1s` orbital
    D
    none of the above.
  • The sigma_(2s) orbital has a higher energy than sigma_(1s)^(**) orbital, sigma(_2s) orbital is bonding while sigma_(1s)^(**) orbital is antibonding because :

    A
    `sigma_(2s)` is planar while `sigma_(1s)^(**)` orbital.
    B
    `sigma_(2s)` is symmetrical while `sigma_(1s)^(**)` is unsymmetrical
    C
    `sigma_(2s)` is nearer to the nuclei than `sigma_(1s)^(**)`
    D
    none of these
  • Assertion: The first ionisation energy of Be is greater than that of B . Reason: 2p-orbital is lower in energy than 2s-orbital.

    A
    If both assertion and reason are true and reason is the correct explanation of assertion
    B
    If the assertion and reason are true but reason is not the correct explanation of assertion.
    C
    If assertion is true but reason is false.
    D
    If assertion is false but reason is true.
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    Assertion :- The first ionization energy of Be is greater than that of B 2p- orbital is lower in energy when 2s- orbital.

    Assertion (A) : The first IE of Be is greater than that of B Reason (R ) : 2p orbitals is lower in energy than 2s

    Comprehension given below is followed by some multiple choice question, Each question has one correct options. Choose the correct option. Molecular orbitals are formed by the overlap of atomic orbitals. Two atomic orbitals combine to form two molecular orbitals called bonding molecular orbital (BMO) and anti-bonding molecular orbital (ABMO). Energy of anti-bonding orbital is raised above the parent atomic orbitals that have combined and hte energy of the bonding orbital is lowered than the parent atomic orbitals. energies of various molecular orbitals for elements hydrogen to nitrogen increase in the order sigma1s lt sigma^(star)1s lt sigma^(star)2s lt ((pi2p_(x))=(pi2p_(y))) lt sigma2p_(z) lt (pi^(star)2p_(x) = pi^(star)2p_(y)) lt sigma^(star)2p_(z) and For oxygen and fluorine order of enregy of molecules orbitals is given below. sigma1s lt sigma^(star)1s lt sigma2s lt sigma^(star)2s lt sigmap_(z) lt (pi2p_(x) ~~ pi2p_(y)) lt (pi^(star)2p_(x)~~ pi^(star)2py) lt sigma^(star)2p_(z) Different atomic orbitalsof one atom combine with those atoms orbitals of the second atom which have comparable energies and proper orientation. Further, if the overlapping is head on, the molecular orbital is called sigma, sigma andif the overlap is lateral, the molecular orbital is called pi, pi . The molecular orbitals are filled with electrons according to the same rules as followed for filling of atomic orbitals. However, the order for filling is not the same for all molecules or their ions. Bond order is one of the most important parameters to compare the strength of bonds. 67) Which of the following pair is expected to have the same bonod order?

    Comprehension given below is followed by some multiple choice question, Each question has one correct options. Choose the correct option. Molecular orbitals are formed by the overlap of atomic orbitals. Two atomic orbitals combine to form two molecular orbitals called bonding molecular orbital (BMO) and anti-bonding molecular orbital (ABMO). Energy of anti-bonding orbital is raised above the parent atomic orbitals that have combined and hte energy of the bonding orbital is lowered than the parent atomic orbitals. energies of various molecular orbitals for elements hydrogen to nitrogen increase in the order sigma1s lt sigma^(star)1sltsigma^(star)2slt((pi2p_(x))=(pi2p_(y)))ltsigma2p_(z)lt(pi^(star)2p_(x) = pi^(star)2p_(y))ltsigma^(star)2p_(z) and For oxygen and fluorine order of enregy of molecules orbitals is given below. sigma1s lt sigma^(star)1s lt sigma2s lt sigma^(star)2s lt sigmap_(z) lt (pi2p_(x) ~~ pi2p_(y)) lt (pi^(star)2p_(x)~~ pi^(star)2py) lt sigma^(star)2p_(z) Different atomic orbitalsof one atom combine with those atoms orbitals of the second atom which have comparable energies and proper orientation. Further, if the overlapping is head on, the molecular orbital is called sigma, sigma andif the overlap is lateral, the molecular orbital is called pi, pi . The molecular orbitals are filled with electrons according to the same rules as followed for filling of atomic orbitals. However, the order for filling is not the same for all molecules or their ions. Bond order is one of the most important parameters to compare the strength of bonds. In which of the following molecules, sigma2p_(z) molecular orbital is filled after pi2p_(x) and pi2p_(y) molecular orbitals?

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