In `XeF_2`, `XeF_4`, and `XeF_6`, the number of lone pairs on `Xe` is, respectively,

Options

A. `4,1,2`
B. `1,2,3`
C. `2,3,1`
D. `3,2,1`

Answer

D

Explanation

The central atom in `Xe` has 8 valence electrons. In `XeF_2`, two electrons are used up to form two bonds with F atoms. This leaves 6 electrons forming 3 lone pairs. In `XeF_4`, four valence `e^(-)s` are used up for bonding leaving out four valence electrons to form two lone pairs. In `XeF_6`, six valence electrons are used up for bonding, leaving out two nonbonding electrons which form one lone pair.