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The correct order of bond angles in the ...

The correct order of bond angles in the molecules, `H_2O`, `NH_3`, `CH_4`, and `CO_2` is

A

`H_2O gt NH_3 gt CH_4 gt CO_2`

B

`H_2O lt NH_3 lt CO_2 lt CH_4`

C

`H_2O lt NH_3 gt CO_2 gt CH_4`

D

`CO_2 gt CH_4 gt NH_3 gt H_2O`

Text Solution

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The correct Answer is:
To determine the correct order of bond angles in the molecules H₂O, NH₃, CH₄, and CO₂, we will analyze the molecular geometry and the bond angles associated with each molecule step by step. ### Step 1: Analyze H₂O (Water) - **Central Atom**: Oxygen (O) - **Valence Electrons**: Oxygen has 6 valence electrons. - **Bonds**: It forms 2 single covalent bonds with 2 hydrogen atoms, using 2 of its valence electrons. - **Lone Pairs**: This leaves 4 valence electrons, which form 2 lone pairs. - **Steric Number**: The steric number is calculated as the number of bonded atoms (2) plus the number of lone pairs (2), giving a steric number of 4. - **Geometry**: The molecular geometry is tetrahedral, but the shape is bent or angular due to the presence of lone pairs. - **Bond Angle**: The bond angle in H₂O is approximately 104.5°. ### Step 2: Analyze NH₃ (Ammonia) - **Central Atom**: Nitrogen (N) - **Valence Electrons**: Nitrogen has 5 valence electrons. - **Bonds**: It forms 3 single covalent bonds with 3 hydrogen atoms, using 3 of its valence electrons. - **Lone Pairs**: This leaves 2 valence electrons, which form 1 lone pair. - **Steric Number**: The steric number is 3 (bonded atoms) + 1 (lone pair) = 4. - **Geometry**: The molecular geometry is tetrahedral, and the shape is trigonal pyramidal. - **Bond Angle**: The bond angle in NH₃ is approximately 107°. ### Step 3: Analyze CH₄ (Methane) - **Central Atom**: Carbon (C) - **Valence Electrons**: Carbon has 4 valence electrons. - **Bonds**: It forms 4 single covalent bonds with 4 hydrogen atoms, using all of its valence electrons. - **Lone Pairs**: There are no lone pairs. - **Steric Number**: The steric number is 4 (bonded atoms) + 0 (lone pairs) = 4. - **Geometry**: The geometry is tetrahedral. - **Bond Angle**: The bond angle in CH₄ is 109.5°. ### Step 4: Analyze CO₂ (Carbon Dioxide) - **Central Atom**: Carbon (C) - **Valence Electrons**: Carbon has 4 valence electrons. - **Bonds**: It forms 2 double bonds with 2 oxygen atoms, using all of its valence electrons. - **Lone Pairs**: There are no lone pairs. - **Steric Number**: The steric number is 2 (bonded atoms) + 0 (lone pairs) = 2. - **Geometry**: The geometry is linear. - **Bond Angle**: The bond angle in CO₂ is 180°. ### Step 5: Arrange the Bond Angles Now that we have the bond angles for each molecule: - H₂O: 104.5° - NH₃: 107° - CH₄: 109.5° - CO₂: 180° ### Final Order of Bond Angles The correct order of bond angles from smallest to largest is: 1. H₂O: 104.5° 2. NH₃: 107° 3. CH₄: 109.5° 4. CO₂: 180° Thus, the final answer is: **H₂O < NH₃ < CH₄ < CO₂**

To determine the correct order of bond angles in the molecules H₂O, NH₃, CH₄, and CO₂, we will analyze the molecular geometry and the bond angles associated with each molecule step by step. ### Step 1: Analyze H₂O (Water) - **Central Atom**: Oxygen (O) - **Valence Electrons**: Oxygen has 6 valence electrons. - **Bonds**: It forms 2 single covalent bonds with 2 hydrogen atoms, using 2 of its valence electrons. - **Lone Pairs**: This leaves 4 valence electrons, which form 2 lone pairs. - **Steric Number**: The steric number is calculated as the number of bonded atoms (2) plus the number of lone pairs (2), giving a steric number of 4. ...
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The correct order of bond angles among the compounds CH_(4) , NH_(3) and H_(2)O is (A) H_(2)O (B) NH_(3) (C) NH_(3) (D) CH_(4) < H_(2)O < NH_(3)

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Knowledge Check

  • The bond angles in molecules H_(2)O, NH_(3), CH_(4) and CO_(2) are in the order :

    A
    `H_(2)O gt NH_(3) gt CH_(4) gt CO_(2)`
    B
    `H_(2)O lt NH_(3) lt CO_(2) lt CH_(4)`
    C
    `H_(2)Olt NH_(3) lt CH_(4) lt CO_(2)`
    D
    `H_(2)O gt NH_(3) lt CH_(4) gt CO_(2)`.
  • The correct order of bond angles (smallest first) in H_2 S, NH_3, BF_3 and SiH_4 is

    A
    `H_2S` lt `SiH_4` lt `NH_3` lt `BF_3`
    B
    `H_2S` lt `NH_3` lt `BF_3` lt `SiH_4`
    C
    `H_2`lt `NH_3`lt `SiH_4`lt`BF_3`
    D
    `NH_3` lt `H_2 S` lt `SiH_4` lt `BF_3`
  • Which of the following is the correct order of bond angle in H_2S , NH_3 , BF_3 and SiH_4 ?

    A
    `H_2Slt NH_3lt BF_3lt SiH_4`
    B
    `NH_3lt H_2Slt SiH_4lt BF_3`
    C
    ` H_2Slt NH_3lt SiH_4lt BF_3`
    D
    ` H_2Slt SiH_4lt NH_3lt BF_3`
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