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Coordinating number of Na^(+) in NaCl is...

Coordinating number of `Na^(+)` in `NaCl` is

A

`4`

B

`3`

C

`6`

D

`5`

Text Solution

Verified by Experts

The correct Answer is:
3

In `NaCl`, each `Na^(+)` ion is present in an octahedral void and is surrounded by `6CI^(-)` ions sitting at the corners of the octahedron.
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Knowledge Check

  • Pick up the correct statement: (a) The crystal of AgBr does not have Schottky defect (b) The crystal system having crystal parameters, a = b != c, alpha= beta= 90^(@), gamma= 120^(@) is for a hexagonal unit cell (c) Ionic compounds having Frenkel defect, generally show a low radius ratio value. (d) The coordination number of Na^(+) ion in NaCl is 4

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    B
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    C
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    D
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  • A : Coordination number of both Na^(+) and Cl^(-) NaCl is 6. R : Second coordination number of Cl^(-) in the NaCl unit is 12.

    A
    If both Assertion & Reason are true and the reason is the correct explanation of the assertion then mark (1)
    B
    If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2)
    C
    If Assertion is true statement but Reason is false then mark (3)
    D
    If both Assertion and Reason are false statements, then mark (4)
  • A : In NaCl coordination number of Cl^(-) ion is 6 but in CsCl coordination number of Cl^(-) ion is 8. R : Ionic radii changes with type of lattice.

    A
    If both Assertion & Reason are true and the reason is the correct explanation of the assertion then mark (1)
    B
    If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2)
    C
    If Assertion is true statement but Reason is false then mark (3)
    D
    If both Assertion and Reason are false statements, then mark (4)
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