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The position of a particle at time t is ...

The position of a particle at time `t` is given by the relation `x (t) = (v_(0))/(A) (1 - e^(-At))`, where `v_(0)` is constant and `A gt 0`. The dimensions of `v_(0)` and `A` respectively

A

`[M^(0) LT^(0)]` and `[T^(-1)]`

B

`[M^(0) LT^(-1)]` and `[T^(-2)]`

C

`[M^(0) LT^(-1)]` and `[T]`

D

`[M^(0) LT^(-1)]` and `[T^(-1)]`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • The position of a particle at time t is given by the relation x(t) = ( v_(0) /( alpha)) ( 1 - c^(-at)) , where v_(0) is a constant and alpha gt 0 . Find the dimensions of v_(0) and alpha .

    A
    `[L^(-1)T^(-1)]``,[ T^(-2)]`
    B
    `[L^(2)T^(-1)]``,[ T^(-1)]`
    C
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    D
    `[LT^(-2)]``,[ T^(1)]`

  • The position x of a particle at time t is given by x=(V_(0))/(a)(1-e^(-at)) , where V_(0) is constant and a gt 0 . The dimensions of V_(0) and a are

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    B
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