A particle is thrown with speed of `50 m//s` at an angle of projection `37^(@)` with the horizontal. Find (a) the time of flight, (b) the maximum height attained and ( c) the horizontal range.
`(sin 37^(@) = (3)/(5), cos 37^(@) = (4)/(5))`

Explanation

To solve the problem step by step, we will use the equations of projectile motion.

### Given:
- Initial speed, \( u = 50 \, \text{m/s} \)
- Angle of projection, \( \theta = 37^\circ \)
- \( \sin 37^\circ = \frac{3}{5} \)
- \( \cos 37^\circ = \frac{4}{5} \)
- Acceleration due to gravity, \( g = 10 \, \text{m/s}^2 \)
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