If in a projection motion, the maximum height is equal to a horizontal range, find the angles of projection `[tan^(-1) (4) = 76^(@)]`

Explanation

`H_(max) = R`
`(u^(2) sin^(2) theta)/(2 g) = (u^(2))/(g)(2 sin theta cos theta) rArr tan theta = 4`
`theta = tan^(-1)(4) = 76^(@)`
Another angle will be `90^(@) - tan^(-1)(4) = 14^(@)`.