Home
Class 11
PHYSICS
If the equation for the displacement of ...

If the equation for the displacement of a particle moving in a circular path is given by `(theta)=2t^(3)+0.5`, where `theta` is in radians and `t` in seconds, then the angular velocity of particle after `2 s` from its start is

A

`8 rad//s`

B

`12 rad//s`

C

`24 rad//s`

D

`36 rad//s`

Text Solution

AI Generated Solution

To find the angular velocity of the particle after 2 seconds, we will follow these steps: ### Step 1: Understand the given function The displacement of the particle in a circular path is given by the equation: \[ \theta(t) = 2t^3 + 0.5 \] where \(\theta\) is in radians and \(t\) is in seconds. ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ROTATIONAL MOTION

    CP SINGH|Exercise Exercise|172 Videos

  • RELATIVE MOTION

    CP SINGH|Exercise EXERCISE|33 Videos

  • SIMPLE HARMONIC MOTION

    CP SINGH|Exercise Exercises|125 Videos

Similar Questions

Explore conceptually related problems

The position of the particle moving along x-axis is given by x=2t-3t^(2)+t^(3) where x is in mt and t is in second.The velocity of the particle at t=2sec is

Angular position theta of a particle moving on a curvilinear path varies according to the equation theta=t^(3)-3t^(2)+4t-2 , where theta is in radians and time t is in seconds. What is its average angular acceleration in the time interval t=2s to t=4s ?

Knowledge Check

  • If the equation for the displacement of a particle moving on a circle path is given by, theta = 2t^(2)+0.5 where, theta is in radian and t is in second, then the angular velocity of the particle after 2 s is

    A
    `8 rad s^(-1)`
    B
    `12 rad s^(-1)`
    C
    `24 rad s^(-1)`
    D
    `36 rad s^(-1)`

  • IF the equation for the displancement of a particle moving on a circular path is given by theta=2t^3+0.5 , where theta is in radius and t is in seconds, then the angular velocity of the particle at t=2 s is

    A
    8 `rad//s`
    B
    12`rad//s`
    C
    24`rad//s`
    D
    36`rad//s`

  • The displacement of a particle moving in a circular path is given by theta = 3 t^(2) + 0.8 , where theta is in radian and t is in seconds . The angular velocity of the particle at t=3 sec . Is

    A
    18 rad/s
    B
    15 rad/s
    C
    12 rad /s
    D
    8 rad /s

    • Similar Questions

    Explore conceptually related problems

    The angular displacement of a particle performing circular motion is theta=(t^(3))/(60)-(t)/(4) where theta is in radian and 't' is in second .Then the angular velocity and angular acceleraion of a particle at the end of 5 s will be

    The angular displacement of a particle performing circular motion is theta=(t^(4))/(60)-(t)/(4) where theta is radian and 't' is in seconds. Then the acceleration of a particle at the end of 10 s will be

    The displacement of a particle moving in a straight line, is given by s = 2t^2 + 2t + 4 where s is in metres and t in seconds. The acceleration of the particle is.

    The angular displacement for a rotating wheel is given by theta(t)=2t^3+5t^2+3 , where t is time in seconds. The angular velocity of the particle after 6 s is

    A particle starts rotating from rest. Its angular displacement is expressed by the following equation theta=0.025t^(2)-0.1t where theta is in radian and t is in seconds. The angular acceleration of the particle is

    Home
    Profile