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The mean radius of the earth's orbit of ...

The mean radius of the earth's orbit of mercury is `6xx10^(10)m`. The mercury will revolve around the sun in nearly

A

`sqrt(2/5)` years

B

`215` years

C

`(2/5)^(2)` years

D

`(2/4)^(3//2)` years

Text Solution

Verified by Experts

The correct Answer is:
D
`T prop r^(3//2)`
`(T_(m))/(T_(e))=((r_(m))/(r_(e)))^(3//2)=((6xx10^(10))/(1.5xx10^(11)))^(3//2)=(2/5)^(3//2)`
`T_(m)=(2/5)^(3//2) T_(e)=(2/5)^(3//2)xx1=(2/5)^(3//2) years`
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Knowledge Check

  • The mean radius of the earth's orbit around the sun is 1.5 xx 10^(11)m and that of the orbit of mercury is 6 xx 10^(10)m . The mercury will revolve around the sun is nearly

    A
    `sqrt((2)/(5))yr`
    B
    `(2)/(5)yr`
    C
    `((2)/(5))^(2)yr`
    D
    `((2)/(5))^(3//2)yr`

  • The mean radius of the earth's orbit round the sun is 1.5xx10^(11) . The mean radius of the orbit of mercury round the sun is 6xx10^(10)m . The mercury will rotate around the sun in

    A
    A year
    B
    Nearly 4 years
    C
    Nearly `1/4` year
    D
    2.5 years

  • The earth revolved around the sun.

    A
    was revolving
    B
    is revolving
    C
    had revolved
    D
    revolves

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