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Calculate the specific heat of a gas at ...

Calculate the specific heat of a gas at constant volume from the following data. Desity of the gas at `N.T.P=19xx10^(-2)kg//m^(3)` , `(C_(p)//C_(v))=1.4,J` `=4.2xx10^(3) J//kcal` : atmospheric pressure `=1.013xx10^(5)N//m^(2)` . `("in" kcal//kg k)`

A

`2.162`

B

`1.612`

C

`1.192`

D

`2.612`

Text Solution

Verified by Experts

The correct Answer is:
C
`c_(v)=(R)/(M(gamma-1))impliesc_(v)=(P)/(JrhoT(gamma-1))`
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Knowledge Check

  • What is the density of a gas at N.T.P. if the rms velocity of the gas molecules is 400m//s ? (Take atmospheric pressure P = 1xx10^(5)N//m^(2) )

    A
    `5/8kg//m^(3)`
    B
    `11/8kg//m^(3)`
    C
    `15/8kg//m^(3)`
    D
    `25/8kg//m^(2)`

  • The ratio of specific heats of a gas is 1.4. if the value of C_(V) is 20.8 J/mol K, then the C_(P) is

    A
    3.93 cal/mol K
    B
    4.93 cal/mol K
    C
    5.93 cal/mol K
    D
    6.93 cal/mol K

  • Calculate the gas constant for 1 g of gas from the following data : C_p=0.245 "cal g"^(-1).^@C^(-1), C_v=0.165" cal g"^(-1).^@C^(-1)and J=4.2 xx10^7 erg cal^(-1)

    A
    `3.36xx10^6"erg g"^(-1 ).^@C^(-1)`
    B
    `2.13xx10^6"erg g"^(-1 ).^@C^(-1)`
    C
    `4.26xx10^6"erg g"^(-1 ).^@C^(-1)`
    D
    `4.57xx10^6"erg g"^(-1 ).^@C^(-1)`

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