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Impure copper containing Fe ,Au ,Ag as...

Impure copper containing Fe ,Au ,Ag as impurities is elecrolytically refined A current of 140 A for 482.25 s decreased the mass of the anode by 22.26 g and increased the mass of cathode by 22.011 g percentage of iron in impure copper is (Given molar mass of Fe =55.5 `mol^(-1)` molar mass of Cu =63.54 g `mol^(-1)`)

A

0.95

B

0.85

C

0.97

D

0.9

Text Solution

Verified by Experts

The correct Answer is:
D
Amount pf impurity
=decreased mass of anode - increased mass of cathode
amount of pure Cu deposited
`W=Zit =(C )/(96500)xxit`
`=(63.54)/(2xx96500)xx140 xx482.5` =22.239 g
`therefore` amount of impurity (Fe) = 22.239 -22.011 = 0.228 g
Now from faraday second law of electrolysis
`("weight of fe deposited")/(0.228) =(27.55)/(31.77)`
`therefore` Weight of Fe `=(27.75 xx0.288)/(22.26) xx100=0.88 =0.09`
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Impure copper containing Fe, Au and Ag as impurities is electrolytically refined. A current of 140 A for 482.5 s decreased the mass of the anode by 22.26 g and increased the mass of the cathode by 22.011g. Calculate the percentage of iron in impure copper. (Given molar mass of Fe=55.5g mol^(-1) , molar mass of Cu=63.54 g mol^(-1) ).

Assume that impure copper contains only Fe, Au and Ag as impurities. After the passage of 140 amperes for 482.5 sec, the mass of the anode decreașşed by 22.26 gm., and that of the cathode increased by 22.011gm. Calculate the \% of iron and copper originally present.

Knowledge Check

  • Assume that impure copper contains only iron, silver and a gold as impurities. After passage of 140A , for 482.5 sec, of the mass of the anode decreased by 22.260g and the cathode increased in mass by 22.011g . Estimate the % iron and % copper originally present.

    A
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    B
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    D
    `Cu =60%, Fe = 40%`

  • Number of atoms in 558.5 g Fe (molar mass Fe= 55.85 g mol^(-1) )

    A
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    B
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