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A bucket full of water is rapidly rot...

A bucket full of water is rapidly rotated in a vertical circle of radius r . It of is found that the water does not fall down from the bucket , even when the bucket is inverted at the highest point . If it continues with this speed , then the normal contact force exerted by the bucket on the water at the lowest point in its path is

A

mg

B

2mg

C

`3mg `

D

`(mg)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
At the highest point , ` v^(2 ) = rg or g= (v^2)/(r ) `
at the lowest point , N - mg `= (mv^(2))/(r )`
` therefore N' = mg + mg = 2mg `
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  • Kick the bucket

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