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One gram of radium is reduced by 2 mili...

One gram of radium is reduced by `2` miligram in `5` yers by `alpha`-decay. Calculate the half-life of radium.

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To find the half-life of radium given that 1 gram is reduced by 2 milligrams in 5 years due to alpha decay, we can follow these steps: ### Step 1: Understand the given data - Initial mass of radium (N₀) = 1 gram - Mass reduced in 5 years = 2 milligrams = 0.002 grams - Remaining mass after 5 years (N) = 1 gram - 0.002 grams = 0.998 grams - Time (t) = 5 years ...
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Knowledge Check

  • A certain mass of radium is reduced by 70% in 2780 years. The decay constant is

    A
    `4.3 xx10^(-4)` per year
    B
    `3.4 xx10^(-4)` per year
    C
    `5.4 xx10^(-4)` per year
    D
    `4.8 xx10^(-4)` per year
  • Uranium ores contain one radium -226 atom for every 2.8 xx 106 uranium -238 atoms. Calculate the half-life of ._92 U6238 given that the half-life of ._88 Ra^226 is 1600 years (._88Ra^226 is a decay product of ._92 U^238 ) :

    A
    `1.75 xx 10^3 years`
    B
    `1600 xx (238)/(92) years`
    C
    `4.5 xx 10^9 years`
    D
    `1600 years`
  • Uranium ores contain one radium -226 atom for every 2.8 xx 10^(6) uranium -238 atoms. Calculate the half-life of ._(88)Ra^(226) is 1600 years (._(88)Ra^(226) is a decay product of ._(92)U^(238)) .

    A
    `1.75 xx 10^(3) years`
    B
    `1600 xx (238)/(92)years`
    C
    `4.5 xx 10^(9) years`
    D
    `1600 xx 238 years`
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