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A ray of light of intensity I is inciden...

A ray of light of intensity I is incident on a parallel glass slab at a point A as show. It undergoes partial reflection and refraction. At each reflaction `25%` of incident energy is reflected. The rays AB and A'B' undergo interference. The ratio `I_(max)//I_(min)` is

A

`4:1`

B

`8:1`

C

`7:1`

D

`49:1`

Text Solution

Verified by Experts

The correct Answer is:
D
`(I_(max))/(I_(min)) = ((sqrt(I_(1))+sqrt(I_(2)))/(sqrt(I_(1))-sqrt(I_(2))))^(2) " " , I_(1) = (I)/(4): I_(2) = (91)/(64)`
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