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The concentration of OH^(-) ions in a 0....

The concentration of `OH^(-)` ions in a `0.050 M HNO_(3)` solution is

A

`2.0xx10^(-13)`

B

`1.0xx10^(-13)`

C

`0.5xx10^(-13)`

D

`1.5xx10^(13)`

Text Solution

Verified by Experts

The correct Answer is:
A
Since `HNO_(3)` is a strong acid, it ionizes almost completely. Thus, the concentration of `H^(+)` ions form `HNO_(3)` is equal to the concentration of `H^(+)` ions form `HNO_(3)` is equal to the concentration of `HNO_(3)`, i.e., `5xx10^(-2)` . The contribution of `H^(+)` ions form water will be negligible.
`K_(w)=C_(H^(+))C_(OH^(-))`
`C_(OH^(-))=(K_(w))/(C_(H^(+)))=(1.0xx10^(-14))/(5xx10^(-2))`
`=2.0xx10^(-13)`
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Knowledge Check

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