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A diagonal of a parallelogram divides it...

A diagonal of a parallelogram divides it into two congruent triangles.

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A diagonal of parallelogram divides it into two congruent triangles.

Show that each diagonal of a parallelogram divide it into two congruent triangles. The following are the steps involved in showing the above result. Arrange them in sequential order. A) In triangleABC and triangleCDA , AB=DC and BC=AD (therefore opposite angles of parallelogram) AC=AC (common side). B) Let ABCD be a parallelogram. Join AC. C) By SSS congruence property, triangleABC ~=triangleCDA . D) Similarly, BD divides the triangle into two congruent triangles.

Prove that each of the following diagonals of a parallelogram divides it into two congurent triangles. The following lowing are the steps involved in proving the above results. Arrange them in sequential order. ltimg src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PS_MATH_VIII_C16_E04_031_Q01.png" width="80%"gt (A) By SSS conguruence property , Delta DAB ~= Delta BCD . (B) Let ABCD be a parallelogram and join BD. (C ) AB=CD,AD=BC (opposite sides of parallelogram) and BD =BD (common side). (D ) Similarly , AC divides the parallelogram into two congruent triangles.

A diagonal of a parallelogram divides it into two triangles of equal area.

A diagonal of a parallelogram divides it into two triangles of equal area. GIVEN : A parallelogram A B C D in which B D is one of the diagonals. TO PROVE : ar ( A B D)=a r( C D B)

Show that the diagonals of a parallelogram divide it into four triangles of equal area.

Show that the diagonals of a parallelogram divide it into four triangles of equal area.

Show that the diagonals of a parallelogram divide it into four triangles of equal area.

Show that the diagonals of a parallelogram divide it into four triangles of equal area. GIVEN : A parallelogram A B C D . The diagonals A C and B D intersect at Odot TO PROVE : a r( O A B)=a r( O B C)=a r( O C D)=a r( A O D)