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A diagonal of a parallelogram divides it...

A diagonal of a parallelogram divides it into two congruent triangles.

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A diagonal of parallelogram divides it into two congruent triangles.

Prove that each of the following diagonals of a parallelogram divides it into two congurent triangles. The following lowing are the steps involved in proving the above results. Arrange them in sequential order. ltimg src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PS_MATH_VIII_C16_E04_031_Q01.png" width="80%"gt (A) By SSS conguruence property , Delta DAB ~= Delta BCD . (B) Let ABCD be a parallelogram and join BD. (C ) AB=CD,AD=BC (opposite sides of parallelogram) and BD =BD (common side). (D ) Similarly , AC divides the parallelogram into two congruent triangles.

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  • Prove that each of the diagonals of a parallelogram divides it into two congruent triangles .The following steps are involved in proving the above result .Arrange them in sequential order . (A) By SSS congruence property , DeltaDAB~=DeltaBCD . (B) Let ABCD be a parallelogram and join BD . ( C) AB=CD,AD =BC (opposite sides of the parallelogram ), and BD =BD(common side) (D) Similarly ,AC divides the parallelogram into two congruent triangles .

    A
    ABCD
    B
    BCAD
    C
    BACD
    D
    CBAD

  • Show that each diagonal of a parallelogram divide it into two congruent triangles. The following are the steps involved in showing the above result. Arrange them in sequential order. A) In triangleABC and triangleCDA , AB=DC and BC=AD (therefore opposite angles of parallelogram) AC=AC (common side). B) Let ABCD be a parallelogram. Join AC. C) By SSS congruence property, triangleABC ~=triangleCDA . D) Similarly, BD divides the triangle into two congruent triangles.

    A
    BACD
    B
    BDAC
    C
    BADC
    D
    BDCA

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    A diagonal of a parallelogram divides it into two triangles of equal area.

    A diagonal of a parallelogram divides it into two triangles of equal area. GIVEN : A parallelogram A B C D in which B D is one of the diagonals. TO PROVE : ar ( A B D)=a r( C D B)

    Show that the diagonals of a parallelogram divide it into four triangles of equal area.

    Show that the diagonals of a parallelogram divide it into four triangles of equal area.

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    Show that the diagonals of a parallelogram divide it into four triangles of equal area. GIVEN : A parallelogram A B C D . The diagonals A C and B D intersect at Odot TO PROVE : a r( O A B)=a r( O B C)=a r( O C D)=a r( A O D)

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