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Sum of cube of first n natural number...

Sum of cube of first n natural number

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Find the sum of cubes of first 10 natural number .

Find the sum of cubes of first 12 natural numbers

Knowledge Check

  • Consider the following statements: 1. The sum of cubes of first 20 natural numbers is 44400. 2. The sum of squares of first 20 natural numbers is 2870. Which of the above statement is/are correct?

    A
    1 only
    B
    2 only
    C
    Both 1 and 2
    D
    Neither 1 nor 2

  • Let S_n denote the sum of the cubes of the first n natural numbers and s_n denote the sum of the first n natural numbers. Then, sum_(r=1)^n(S_r)/(8_r) is equal to

    A
    `(n(n+1)(n+2))/6`
    B
    `(n(n+1))/2`
    C
    `(n^2+3n+2)/2`
    D
    None of these

  • let S_(n) denote the sum of the cubes of the first n natural numbers and s_(n) denote the sum of the first n natural numbers , then sum_(r=1)^(n)(S_(r))/(s_(r)) equals to

    A
    `(n(n+1)(n+2))/(6)`
    B
    `(n(n+1))/(2)`
    C
    `(n^(2)+3n+2)/(2)`
    D
    None of these

    • Similar Questions

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    Property 3 The sum of the cubes of first n natural numbers is equal to the square of their sum.That is 1^(3)+2^(3)+3^(3)+.........+n^(3)=(1+2+3+......+n)^(2)

    The sum of squares of first n natural numbers is given by 1/6 n (n+1)(2n+1) or 1/6 (2n^3 + 3n^2 + n) . Find the sum of squares of the first 10 natural numbers.

    Let S_(n) denote the sum of the cubes of the first n natural numbers and s_(n) denote the sum of the first n natural numbers.Then sum_(r=1)^(n)(S_(r))/(s_(r)) is equal to

    Find the sum of the cubes of first 15 natural numbers.

    The mean of the cubes of the first n natural numbers is

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