Sum of cube of first n natural number

Find the sum of cubes of first 10 natural number .

Find the sum of cubes of first 12 natural numbers

Consider the following statements: 1. The sum of cubes of first 20 natural numbers is 44400. 2. The sum of squares of first 20 natural numbers is 2870. Which of the above statement is/are correct?

Property 3 The sum of the cubes of first n natural numbers is equal to the square of their sum.That is 1^(3)+2^(3)+3^(3)+.........+n^(3)=(1+2+3+......+n)^(2)

The sum of squares of first n natural numbers is given by 1/6 n (n+1)(2n+1) or 1/6 (2n^3 + 3n^2 + n) . Find the sum of squares of the first 10 natural numbers.

Let S_(n) denote the sum of the cubes of the first n natural numbers and s_(n) denote the sum of the first n natural numbers.Then sum_(r=1)^(n)(S_(r))/(s_(r)) is equal to

let S_(n) denote the sum of the cubes of the first n natural numbers and s_(n) denote the sum of the first n natural numbers , then sum_(r=1)^(n)(S_(r))/(s_(r)) equals to

Find the sum of the cubes of first 15 natural numbers.