A ball is dropped from a height of `5 m` onto a sandy floor and penetrates the sand up to 1 m before coming to rest. The retardation of the ball in sand (assuming it to be uniform) will be

Options

A. `25 m//s^(2)`
B. `50 m//s^(2)`
C. `75 m//s^(2)`
D. `100 m//s^(2)`

Answer

B

Explanation

`A` to `B: v^(2)=2gxx5=100`
`B` to `C: 0=v^(2)-2axx1`
`a=50 m//s^(2)`