Home
Class 11
PHYSICS
For body moving with uniform acceleratio...

For body moving with uniform acceleration `a`, initial and final velocities in a time interval `t` are `u` and `v` respectively. Then its average velocity in the time interval `t` is

A

`(v+at)`

B

`(v-(at)/(2))`

C

`(v-at)`

D

`(u-(at)/(2))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the average velocity of a body moving with uniform acceleration, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information**: - The body has an initial velocity \( u \) and a final velocity \( v \). - The acceleration is uniform, denoted as \( a \). - The time interval during which this motion occurs is \( t \). 2. **Formula for Average Velocity**: - The average velocity \( v_{\text{avg}} \) can be defined as the total distance traveled divided by the total time taken: \[ v_{\text{avg}} = \frac{s}{t} \] where \( s \) is the distance traveled during the time interval \( t \). 3. **Distance Traveled with Uniform Acceleration**: - The formula for distance \( s \) when an object is moving with uniform acceleration is given by: \[ s = ut + \frac{1}{2} a t^2 \] 4. **Substituting for Average Velocity**: - Substitute the expression for \( s \) into the average velocity formula: \[ v_{\text{avg}} = \frac{ut + \frac{1}{2} a t^2}{t} \] - Simplifying this gives: \[ v_{\text{avg}} = u + \frac{1}{2} a t \] 5. **Relate Final Velocity to Initial Velocity**: - From the equation of motion, we know: \[ v = u + at \] - Rearranging this gives: \[ u = v - at \] 6. **Substituting \( u \) in Average Velocity Formula**: - Now substitute \( u \) in the average velocity formula: \[ v_{\text{avg}} = (v - at) + \frac{1}{2} a t \] - Simplifying this gives: \[ v_{\text{avg}} = v - at + \frac{1}{2} a t = v - \frac{1}{2} a t \] 7. **Final Expression for Average Velocity**: - Thus, the average velocity can be expressed as: \[ v_{\text{avg}} = v - \frac{1}{2} a t \] ### Conclusion: The average velocity \( v_{\text{avg}} \) of the body moving with uniform acceleration over the time interval \( t \) is given by: \[ v_{\text{avg}} = u + \frac{1}{2} a t \] or equivalently, \[ v_{\text{avg}} = v - \frac{1}{2} a t \]

To find the average velocity of a body moving with uniform acceleration, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information**: - The body has an initial velocity \( u \) and a final velocity \( v \). - The acceleration is uniform, denoted as \( a \). - The time interval during which this motion occurs is \( t \). ...
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A STRAIGHT LINE

    NARAYNA|Exercise Level 2 C.W|25 Videos
  • MOTION IN A STRAIGHT LINE

    NARAYNA|Exercise Level 3 C.W|25 Videos
  • MOTION IN A STRAIGHT LINE

    NARAYNA|Exercise C.U.Q|42 Videos
  • MOTION IN A PLANE

    NARAYNA|Exercise Level-II(H.W)|31 Videos
  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise PASSAGE TYPE QUESTION|6 Videos

Similar Questions

Explore conceptually related problems

For a body moving withuniform acceleration 'a', initial and final velocities in a time interval are 'u' and respectively.Then,its average velocity in the time interval T is

A particle moves in a straight line with uniform acceleration. Its velocity at time t=0 is v_1 and at time t=t is v_2. The average velocity of the particle in this time interval is (v_1 + v_2)/2 . Is this statement true or false?

A particle move with a velocity v=alpha t^(3) along a straight line.The average velocity in time interval t=0 to t=T is

Statement-I : A particle moves in a straight line with constant acceleration. The average velocity of this particle cannot be zero in any time interval. Statement-II : For a particle moving in straight line with constant acceleration, the average velocity in a time interval is (u+v)/(2) , where u and v are initial and final velocity of the particle of the given time interval.

An object is moving with uniform acceleration a. Its initial velocity is u and after time t its velocity is v. The equation of its motion is v = u + at. The velocity (along y-axis) time (along x-axis) graph shall be a straight line

A body A moves with a uniform acceleration a and zero initial velocity. Another body B, starts from the same point moves in the same direction with a constant velocity v. The two bodies meet after a time t. The value of t is

Assertion : In the upsilon-t diagram as shown in figure, average velocity between the interval t = 0 and t = t_(0) is independent of t_(0) Reason : Average velocity in the given interval is (1)/(2)upsilon_(m) .

If velocity of a particle is given by v=(2t+3)m//s . Then average velocity in interval 0letle1 s is :

NARAYNA-MOTION IN A STRAIGHT LINE-Level 1 C.W
  1. A body is moving along the circumference of a circle of radius R and c...

    Text Solution

    |

  2. A body completes one round of a circle of radius R in 20 second. The d...

    Text Solution

    |

  3. If a body covers first half of its journey with uniform speed v(1) and...

    Text Solution

    |

  4. A car is moving along a straight (OP). It moves from O to P in 18 seco...

    Text Solution

    |

  5. For body moving with uniform acceleration a, initial and final velocit...

    Text Solution

    |

  6. A body moves with a velocity of 3 m//s due east and then turns due nor...

    Text Solution

    |

  7. If a body travles 30 m in an interval of 2 s and 50 m in the next inte...

    Text Solution

    |

  8. A bullet travelling horizontally looses 1//20^(th) of its velocity whi...

    Text Solution

    |

  9. If S(n)=2+0.4n find initial velocity and acceleration

    Text Solution

    |

  10. A particle starts moving from rest under uniform acceleration it trave...

    Text Solution

    |

  11. A particle is moving in a straight line with initial velocity u and un...

    Text Solution

    |

  12. A particle is moving with uniform acceleration along a straight line A...

    Text Solution

    |

  13. A car moving on a straight road accelerated from a speed of 4.1 m//s t...

    Text Solution

    |

  14. A body projected vertically upwards with a velocity of 19.6 m//s reach...

    Text Solution

    |

  15. A ball is thrown straight upward with a speed v from a point h meter a...

    Text Solution

    |

  16. A ball is dropped on the floor from a height of 10m. It rebounds to a ...

    Text Solution

    |

  17. A body freely falling from the rest has velocity v after it falls thro...

    Text Solution

    |

  18. A ball A is dropped from a building of height 45 m. Simultaneously a...

    Text Solution

    |

  19. Two cars 1 & 2 starting from rest are moving with speeds V(1) and V(2)...

    Text Solution

    |

  20. Two cars are travelling towards each other on a straight road at veloc...

    Text Solution

    |