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A parachutist after bailing out falls 50...

A parachutist after bailing out falls 50 m without friction. When parachute opens, it decelerates at `2 m//s^(2)` he reaches the ground with a speed of `3 m//s` at what height did he bail out ?

A

91 m

B

182 m

C

293 m

D

111 m

Text Solution

Verified by Experts

The correct Answer is:
C
`u=sqrt(2gxxH)" "(g=9.8 m//s^(2))`
`v^(2)-u^(2)=2as`, height at which he bails out `=(H+s)`
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Knowledge Check

  • A parachutist after bailing out falls 50m without friction. When parachute opens, it decelerates at 2m//s^2 . He reaches the ground with a speed of 3m//s . At what height, did the bail out?

    A
    (a) 182m
    B
    (b) 91m
    C
    (c) 111m
    D
    (d) 293m

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    180 m
    B
    280 m
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    380 m
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    480 m

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    A
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    B
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    C
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    D
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