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A parachutist after bailing out falls 50...

A parachutist after bailing out falls 50 m without friction. When parachute opens, it decelerates at `2 m//s^(2)` he reaches the ground with a speed of `3 m//s` at what height did he bail out ?

A

91 m

B

182 m

C

293 m

D

111 m

Text Solution

Verified by Experts

The correct Answer is:
C
`u=sqrt(2gxxH)" "(g=9.8 m//s^(2))`
`v^(2)-u^(2)=2as`, height at which he bails out `=(H+s)`
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