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There are two groups of compounds A and ...

There are two groups of compounds A and B. Groups A contains three compounds `Px_(4), Qy_(3), Rz_(2)`. Groups B also contains three compounds `Sx_(4), Ty_(3), Uz_(2)`. Hybridization of each central atom of group A compounds is same as that of iodine in `IBrCl^(-)` while in group B compounds it is same as that of iodine `IBrCl^(+)`. Substituents X, Y and Z exhibit covalency of one in ground state. Then find the value of x/y.
Where, x and y are total number of lone pair present at central atoms of compounds of group A and B respectively.

Text Solution

Verified by Experts

The correct Answer is:
`2`
`I_(3)^(-)rArrsp^(3)d`
Group A
`AsF_(4)^(+)rArrsp^(3)`
Group B
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  • The group of heterocylic compounds is:

    A
    Phenol, Furane
    B
    Furane, Thiophene
    C
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    D
    Furane, Aniline

  • The compound with an isopropyl group is

    A
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    B
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    C
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    D
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  • Which member of group 13 does not exhibit the group valency in its compounds?

    A
    Boron
    B
    Aluminium
    C
    Gallium
    D
    Thallium

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