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Electrolysis is an important technique f...

Electrolysis is an important technique for extraction of metals, and each ion of the solution needs a minimum voltage to get discharged and this value is expressed in terms of discharge potential. For some metal ions the discharge potentials follow the order given below :
`Li^(+) gt K^(+) gt Ca^(2+) gt Na^(+) gt Mg^(2+) gt Al^(3+) gt Zn^(2+) gt Fe^(2+) gt Ni^(2+) gt H_(3)O^(+) gt Cu^(2+) gt Hg_(2)^(2+) gt Ag^(+) gt Au^(3+)`
For some anions the discharge potentials are in the order :
`SO_(4)^(2-) gt NO_(3)^(-) gt OH^(-) gt Br^(-) gt I^(-)`
When aqueous solution of cupric bromide is electrolyzed the product obtained at cathode will be :

A

Cu

B

`H_(2)`

C

`Br_(2)`

D

`O_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
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Electrolysis is an important technique for extraction of metals, and each ion of the solution needs a minimum voltage to get discharged and this value is expressed in terms of discharge potential. For some metal ions the discharge potentials follow the order given below : Li^(+) gt K^(+) gt Ca^(2+) gt Na^(+) gt Mg^(2+) gt Al^(3+) gt Zn^(2+) gt Fe^(2+) gt Ni^(2+) gt H_(3)O^(+) gt Cu^(2+) gt Hg_(2)^(2+) gt Ag^(+) gt Au^(3+) For some anions the discharge potentials are in the order : SO_(4)^(2-) gt NO_(3)^(-) gt OH^(-) gt Br^(-) gt I^(-) When conc. H_(2)SO_(4) is electrolysed with high current using Pt electrodes, the product obtained at anode is :

Electrolysis is an impotant technique for extraction of metals, and each of the solution needs a minimum voltage to get discharged and this value is expressed in terms of discharge potential. For some metal ions the discharge potential follow the order given below: Li^(+) gt K^(+) gt Ca^(2+) gt Na^(+) gt Mg^(2+) gt Al^(3+) gt Zn^(2+) gt Fe^(2+) gt Ni^(2+) H_(3)O gt Cu^(2+) gt H_(2)^(2+) gt Ag^(+) gt Au^(3+) . For some anions the discharge potentials:- SO_(4)^(2-) gt BO_(3)^(-) OH^(-) gt Br^(-) gt I^(-) When aqueous solution of cupric bromide is electrolysed, the product obtained at cathode will be

Knowledge Check

  • Electrolysis is an important technique for extraction of metals, and each ion of the solution needs a minimum voltage to get discharged and this value is expressed in terms of discharge potential. For some metal ions the discharge potentials follow the order given below : Li^(+) gt K^(+) gt Ca^(2+) gt Na^(+) gt Mg^(2+) gt Al^(3+) gt Zn^(2+) gt Fe^(2+) gt Ni^(2+) gt H_(3)O^(+) gt Cu^(2+) gt Hg_(2)^(2+) gt Ag^(+) gt Au^(3+) For some anions the discharge potentials are in the order : SO_(4)^(2-) gt NO_(3)^(-) gt OH^(-) gt Br^(-) gt I^(-) The product formed at anode and cathode, when dilute H_(2)SO_(4) is electrolysed are :

    A
    `SO_(2),H_(2)`
    B
    `SO_(3),H_(2)`
    C
    `H_(2)S_(2)O_(8),H_(2)`
    D
    `O_(2),H_(2)`

  • Electrolysis is an important technique for extraction of metals, and each ion of the solution needs a minimum voltage to get discharged and this value is expressed in terms of discharge potential. For some metal ions the discharge potentials follow the order given below : Li^(+) gt K^(+) gt Ca^(2+) gt Na^(+) gt Mg^(2+) gt Al^(3+) gt Zn^(2+) gt Fe^(2+) gt Ni^(2+) gt H_(3)O^(+) gt Cu^(2+) gt Hg_(2)^(2+) gt Ag^(+) gt Au^(3+) For some anions the discharge potentials are in the order : SO_(4)^(2-) gt NO_(3)^(-) gt OH^(-) gt Br^(-) gt I^(-) The product formed at anode and cathode, when dilute H_(2)SO_(4) is electrolysed are :

    A
    `SO_(2),H_(2)`
    B
    `SO_(3),H_(2)`
    C
    `H_(2)S_(2)O_(8),H_(2)`
    D
    `O_(2),H_(2)`

  • Electrolysis is an important technique for extraction of metals, and each ion of the solution needs a minimum voltage to get discharged and this value is expressed in terms of discharge potential. For some metal ions the discharge potentials follow the order given below : Li^(+) gt K^(+) gt Ca^(2+) gt Na^(+) gt Mg^(2+) gt Al^(3+) gt Zn^(2+) gt Fe^(2+) gt Ni^(2+) gt H_(3)O^(+) gt Cu^(2+) gt Hg_(2)^(2+) gt Ag^(+) gt Au^(3+) For some anions the discharge potentials are in the order : SO_(4)^(2-) gt NO_(3)^(-) gt OH^(-) gt Br^(-) gt I^(-) When conc. H_(2)SO_(4) is electrolysed with high current using Pt electrodes, the product obtained at anode is :

    A
    `SO_(2)`
    B
    `SO_(3)`
    C
    `O_(2)`
    D
    `H_(2)S_(2)O_(8)`

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