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If A={0,pi/6,pi/4,pi/3,pi/2} and f:Ato B...

If `A={0,pi/6,pi/4,pi/3,pi/2} and f:Ato B` is a surjection defined by `f(x)=cosx` then find B.

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Knowledge Check

  • Let f: { - pi/3, (2pi)/(3)} rarr [0, 4] be a function defined as f(x)=sqrt(3) sin x - cos x + 2 . Then f^(-1)(x) is given by

    A
    `sin^(-1)((x-2)/(2))- pi/6`
    B
    `sin^(-1)((x-2)/(2))+pi/6`
    C
    `(2pi)/(3) + cos^(-1)((x-2)/(2))`
    D
    none of these

  • The number of stationary points of f(x) = cosx in [0,2pi] are

    A
    1
    B
    2
    C
    3
    D
    4

  • If A={x inR//(pi)/(4)lexle(pi)/(3)} and f(x)=sinx-x, then f(A) is equal to

    A
    `[(sqrt3)/(2)-(pi)/(3),(1)/(sqrt2)-(pi)/(4)]`
    B
    `[(-1)/(sqrt2)-(pi)/(4),(sqrt3)/(2)-(pi)/(3)]`
    C
    `[-(pi)/(3),-(pi)/(4)]`
    D
    `[(pi)/(4),(pi)/(3)]`

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    Find the area under the curve f(x)=cosx in [0, 2pi ]

    Let f:[0,4pi] to [0, pi] be defined by f(x)=cos^(-1)(cosx) . The number of points x in [0,4pi] satisfying the equation f(x)=(10-x)/10 is

    If the function f:{-1,1} to{0,2}, defined by f(x)=ax+b is a surjection, then find a & b.

    If the function f: { -1, 1} to {0,2} , defined by f(x) = ax+b is a surjection, then find a & b.

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