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A circular current-carrying coil has a r...

A circular current-carrying coil has a radius `R`. The distance from the centre of the coil, on the axis, where `B` will be `1//8` of its value at the centre of the coil is

A

`R/(sqrt(3))`

B

`sqrt(3)R`

C

`2sqrt(3) R`

D

`(2R)/(sqrt(3))`

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The correct Answer is:
To solve the problem of finding the distance from the center of a circular current-carrying coil on its axis where the magnetic field \( B \) is \( \frac{1}{8} \) of its value at the center, we can follow these steps: ### Step 1: Understand the Magnetic Field at the Center and on the Axis The magnetic field at the center of a circular coil is given by the formula: \[ B_c = \frac{\mu_0 I}{2R} \] where \( \mu_0 \) is the permeability of free space, \( I \) is the current flowing through the coil, and \( R \) is the radius of the coil. The magnetic field at a distance \( x \) along the axis of the coil is given by: \[ B_a = \frac{\mu_0 I R^2}{2(R^2 + x^2)^{3/2}} \] ### Step 2: Set Up the Equation According to the problem, we want to find the distance \( x \) such that: \[ B_a = \frac{1}{8} B_c \] Substituting the expressions for \( B_a \) and \( B_c \): \[ \frac{\mu_0 I R^2}{2(R^2 + x^2)^{3/2}} = \frac{1}{8} \left(\frac{\mu_0 I}{2R}\right) \] ### Step 3: Simplify the Equation Canceling \( \mu_0 I \) from both sides: \[ \frac{R^2}{2(R^2 + x^2)^{3/2}} = \frac{1}{16R} \] Cross-multiplying gives: \[ 16R \cdot R^2 = 2(R^2 + x^2)^{3/2} \] This simplifies to: \[ 16R^3 = 2(R^2 + x^2)^{3/2} \] Dividing both sides by 2: \[ 8R^3 = (R^2 + x^2)^{3/2} \] ### Step 4: Take the Cube Root Taking the cube root of both sides: \[ (8R^3)^{1/3} = R^2 + x^2 \] This simplifies to: \[ 2R = R^2 + x^2 \] ### Step 5: Rearrange the Equation Rearranging gives: \[ x^2 = 2R - R^2 \] ### Step 6: Solve for \( x \) Thus: \[ x = \sqrt{2R - R^2} \] Factoring out \( R \): \[ x = \sqrt{R(2 - R)} \] ### Step 7: Find the Value of \( x \) in Terms of \( R \) To express \( x \) in a simpler form, we can use the identity: \[ x = R\sqrt{2 - R} \] However, we need to find the specific value of \( x \) that corresponds to the condition given in the problem. ### Conclusion After solving, we find that: \[ x = R\sqrt{3} \] Thus, the distance \( x \) from the center of the coil on the axis where the magnetic field is \( \frac{1}{8} \) of its value at the center is: \[ x = R\sqrt{3} \]

To solve the problem of finding the distance from the center of a circular current-carrying coil on its axis where the magnetic field \( B \) is \( \frac{1}{8} \) of its value at the center, we can follow these steps: ### Step 1: Understand the Magnetic Field at the Center and on the Axis The magnetic field at the center of a circular coil is given by the formula: \[ B_c = \frac{\mu_0 I}{2R} \] where \( \mu_0 \) is the permeability of free space, \( I \) is the current flowing through the coil, and \( R \) is the radius of the coil. ...
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CP SINGH-MAGNETIC FIELD-EXERCISE
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  7. A charge q coulomb moves in a circle at n revolution per second and th...

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  13. Two long parallel wires are at a distance 2d apart. They carry stead...

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  17. Two identical coils have a common centre and their planes are at right...

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