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A 0.21 H inductor and a 12 ohm resistanc...

A `0.21 H` inductor and a `12 ohm` resistance are connected in series to a `220 V`. `50 Hz` ac source. Calculate the current in the circuit and the phase angle between the current and the source voltage.

Text Solution

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`X_(L) = omega L = 2 pi fL = 2 pi xx 50 xx 0.21 = 21 pi Omega`
`Z = sqrt(R^(2) + X_(L)^(2)) = sqrt(12^(2) + (21 pi)^(2)) = sqrt(144 + 4348)`
`Z = sqrt(4492) ~= 67.01 Omega , I + (V)/(Z) = (220)/(67.02) = 3.28 A`
`phi = tan^(-1) ((X_(L))/(R )) = tan^(-1) ((21 pi)/(12))`
The current will lag applied voltage by an angle `tan^(-1) ((21 pi)/(12))`
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