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If have vertex of a parabola be at origi...

If have vertex of a parabola be at origin and directrix be `x + 5 =0,` then its latus pectum is

A

5

B

10

C

20

D

40

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to find the length of the latus rectum of a parabola given its vertex and directrix. ### Step-by-Step Solution: 1. **Identify the Vertex and Directrix:** - The vertex of the parabola is given as the origin (0, 0). - The directrix is given by the equation \( x + 5 = 0 \), which simplifies to \( x = -5 \). 2. **Determine the Orientation of the Parabola:** - Since the vertex is at the origin and the directrix is a vertical line (x = -5), the parabola opens to the right. 3. **Find the Value of 'a':** - The distance from the vertex to the directrix is equal to 'a'. - The vertex is at (0, 0) and the directrix is at \( x = -5 \). - The distance from the vertex to the directrix is: \[ |0 - (-5)| = 5 \] - Therefore, \( a = 5 \). 4. **Calculate the Length of the Latus Rectum:** - The length of the latus rectum of a parabola is given by the formula: \[ \text{Length of Latus Rectum} = 4a \] - Substituting the value of 'a': \[ \text{Length of Latus Rectum} = 4 \times 5 = 20 \] 5. **Final Answer:** - The length of the latus rectum is \( 20 \).
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Knowledge Check

  • If vertex of a parabola is origin and directrix is x + 7 = 0 , then its latus rectum is

    A
    7
    B
    14
    C
    28
    D
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  • If the vertex of a parabola is the point (-3,0) and the directrix is the line x+5=0 , then its equation is

    A
    `y^2 = 8 (x+3)`
    B
    `x^2 = 8 (y + 3)`
    C
    `y^2 =-8(x+3)`
    D
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    A
    (0,0)
    B
    (0,4)
    C
    (4,0)
    D
    None of these.
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