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A ring and a disc have same mass and sam...

A ring and a disc have same mass and same radius. Ratio of moments of inertia of the ring about a tangent in its plane to that of the disc about its diameter is

A

`2:1`

B

`4:1`

C

`6:1`

D

`8:1`

Text Solution

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The correct Answer is:
To solve the problem of finding the ratio of moments of inertia of a ring about a tangent in its plane to that of a disc about its diameter, we can follow these steps: ### Step 1: Define the Mass and Radius Let the mass of both the ring and the disc be \( m \) and the radius be \( r \). ### Step 2: Moment of Inertia of the Ring The moment of inertia \( I \) of a ring about an axis through its center and perpendicular to its plane is given by: \[ I_{\text{ring, center}} = m r^2 \] To find the moment of inertia about a tangent in its plane, we can use the **Parallel Axis Theorem**, which states: \[ I = I_{\text{cm}} + m d^2 \] where \( I_{\text{cm}} \) is the moment of inertia about the center of mass, and \( d \) is the distance from the center of mass to the new axis. For a tangent, \( d = r \): \[ I_{\text{ring, tangent}} = I_{\text{ring, center}} + m r^2 = m r^2 + m r^2 = 2 m r^2 \] ### Step 3: Moment of Inertia of the Disc The moment of inertia \( I \) of a disc about an axis through its center and perpendicular to its plane is given by: \[ I_{\text{disc, center}} = \frac{1}{2} m r^2 \] Using the **Perpendicular Axis Theorem**, for a disc, the moment of inertia about its diameter (which is one of the axes in its plane) is: \[ I_{\text{disc, diameter}} = \frac{1}{2} I_{\text{disc, center}} = \frac{1}{2} \left(\frac{1}{2} m r^2\right) + \frac{1}{2} \left(\frac{1}{2} m r^2\right) = \frac{1}{4} m r^2 + \frac{1}{4} m r^2 = \frac{1}{2} m r^2 \] ### Step 4: Calculate the Ratio Now, we can find the ratio of the moments of inertia: \[ \text{Ratio} = \frac{I_{\text{ring, tangent}}}{I_{\text{disc, diameter}}} = \frac{2 m r^2}{\frac{1}{2} m r^2} = \frac{2}{\frac{1}{2}} = 4 \] ### Final Answer Thus, the ratio of the moments of inertia of the ring about a tangent in its plane to that of the disc about its diameter is: \[ \text{Ratio} = 4:1 \] ---
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Knowledge Check

  • A ring and a disc have same mass and same radius. Then ratio of moment of inertia of ring to the moment of inertia of disc is

    A
    4
    B
    2
    C
    `0.5`
    D
    1
  • Moment of inertia of a ring about a tangent to the circle of the ring is

    A
    `(2)/(5) MR^2`
    B
    `(2)/(3) MR^2`
    C
    `(3)/(2) MR^2`
    D
    None of these
  • The moment of inertia of a ring about its geometrical axis is I, then its moment of inertia about its diameter will be

    A
    1 I
    B
    I/2
    C
    I
    D
    I/4
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