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If vec(a) and vec(b) are two vectors the...

If `vec(a) and vec(b)` are two vectors then the value of `(vec(a) + vec(b)) xx (vec(a) - vec(b))` is

A

`2(vec(b) xx vec(a))`

B

`-2(vec(b) xx vec(a))`

C

`(vec(b) xx vec(a))`

D

`vec(a) xx vec(b)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of the expression \((\vec{a} + \vec{b}) \times (\vec{a} - \vec{b})\). ### Step-by-Step Solution: 1. **Apply the Cross Product Distributive Property**: We can expand the expression using the distributive property of the cross product: \[ (\vec{a} + \vec{b}) \times (\vec{a} - \vec{b}) = \vec{a} \times \vec{a} - \vec{a} \times \vec{b} + \vec{b} \times \vec{a} - \vec{b} \times \vec{b} \] 2. **Evaluate the Cross Products**: - The cross product of any vector with itself is zero: \[ \vec{a} \times \vec{a} = \vec{0} \] \[ \vec{b} \times \vec{b} = \vec{0} \] - Thus, we can simplify the expression: \[ \vec{0} - \vec{a} \times \vec{b} + \vec{b} \times \vec{a} - \vec{0} = -\vec{a} \times \vec{b} + \vec{b} \times \vec{a} \] 3. **Use the Property of Cross Products**: The cross product is anti-commutative, meaning: \[ \vec{b} \times \vec{a} = -(\vec{a} \times \vec{b}) \] Therefore, we can substitute: \[ -\vec{a} \times \vec{b} - \vec{a} \times \vec{b} = -2\vec{a} \times \vec{b} \] 4. **Final Result**: Thus, the value of the expression \((\vec{a} + \vec{b}) \times (\vec{a} - \vec{b})\) is: \[ -2\vec{a} \times \vec{b} \] ### Summary: The final answer is: \[ (\vec{a} + \vec{b}) \times (\vec{a} - \vec{b}) = -2\vec{a} \times \vec{b} \]
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TARGET PUBLICATION-SCALARS AND VECTORS-Competitive Thinking
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  5. A force vec F = prop hat i + 3 hat j + 6 hat k is acting at a point ve...

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  6. The velocity of a particle of mass m is vec(v) = 5 hat(i) + 4 hat(j) +...

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  9. The component of a vector r along X-axis will have maximum value if

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  12. Consider a particle on which constant forces vec(F) = hat(i) + 2hat(j)...

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  17. If vec(a) and vec(b) are two vectors then the value of (vec(a) + vec(b...

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