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What is potential of half cell containin...

What is potential of half cell containing zinc electrode in 0.01 M`ZnSO_(4)` ? (`E^(0) = -0.763 V`)

A

`+0.763 V`

B

`-0.763 V`

C

`-0.822 V`

D

`-0.70 V`

Text Solution

Verified by Experts

The correct Answer is:
C
`E=E^(0)+(RT)/(nF)` log`[M^(+n)]`
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Knowledge Check

  • What is the potential of a half-cell consisting of zinc electrode in 0.01m ZnSO_(4) solution at 258^(@)C(E^(@)=0.763V)

    A
    0.8221 V
    B
    8.221 V
    C
    0.5282 V
    D
    9.232 V

  • Calculate the reduction potential of a half-cell consisting of platinum electrode immersed in 2.0 M Fe^(2+) and 0.02 M Fe^(3+) . Given E_(Fe^(3+)//Fe^(2+))^(@)=0.771V

    A
    0.653 V
    B
    0.889 V
    C
    0.683 V
    D
    2.771 V

  • Calculate the standard potential of the cell ,If the standard electrode potentials of Zn^(2+)//Zn and Ag^(+) //Ag are -0.763 V and + 0.799 V respectively .

    A
    0.036 V
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    1.56 V
    C
    `-1.562V`
    D
    0.799V

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    Calculate the potential for half cell containing 0.10 M K_(2)Cr_(2)O_(7)(aq),0.20" M "Cr^(3+)(aq) and 1.0xx10^(-4)M H^(+)(aq) . The half-cell reaction is Cr_(2)O_(7)^(2-)(aq)+14H^(+)(aq)+6e^(-)to2Cr^(3+)(aq)+7H_(2)O(l) and the standard electrode potential is given as E^(@)=1.33V .

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