Home
Class 12
CHEMISTRY
CaC(2) + N(2) to...

`CaC_(2) + N_(2) to`

A

`CaCN_(2)`

B

`CaCN_(2)` and C

C

`CaCN_(2)+N_(2)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B

When calcium carbide reacts with nitrogen at `1000^(@)C`, calcium cyanide and carbon is formed.
`CaC_(2) +N_(2) overset(1000^(@)C)to underset("Calcium cyanide")(CaCN_(2)+C)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • S AND P BLOCK ELEMENTS

    ERRORLESS |Exercise Ordinary thinking (Oxygen family)|109 Videos
  • S AND P BLOCK ELEMENTS

    ERRORLESS |Exercise Ordinary thinking (Halogen family)|180 Videos
  • S AND P BLOCK ELEMENTS

    ERRORLESS |Exercise Ordinary thinking (carbon family)|86 Videos
  • Practical Organic Chemistry

    ERRORLESS |Exercise JEE Ssection (More than one choice correct answer)|16 Videos
  • SOLID STATE

    ERRORLESS |Exercise JEE section (Numeric )|1 Videos

Similar Questions

Explore conceptually related problems

CaC_(2) + H_(2)O to

Complete the following reaction : CaC_(2) + 2H_(2)O to -------- + ---------

Knowledge Check

  • {:(BaC_(2) + N_(2) overset(Delta)rarr (A)),(CaC_(2) + N_(2) overset(Delta)rarr (B)):} (A) and (B) are

    A
    `BaCN_(2), CaCN_(2)`
    B
    `Ba(CN)_(2), Ca (CN)_(2)`
    C
    `Ba(CN)_(2), CaCN_(2)`
    D
    none of the above
  • Polyethene can be prepard by CaC_(2) by the following sequence of reactions . CaC_(2) + H_(2)O to CaO + C_(2)H_(2) C_(2)H_(2) + H_(2) to C_(2)H_(4) nC_(2)H_(4)to (C_(2)H_(4))_(n) " (Polythene)" The mass in kg of polythene that can be prepared by 20 kg CaC_(2) .

    A
    4.1 kg
    B
    8.75 kg
    C
    3.78 kg
    D
    10 kg
  • Polyethlene can be produced from calcium carbide according to the following sequence of reactions: CaC_(2)+ H_(2)O to CaO + HC = CH n(HC-= CH)+nH_(2) to (CH_(2) - CH_(2))_(n) The mass of polyethylene which can be produced from 20.0 Kg of pure CaC_(2) is

    A
    6.75 kg
    B
    7.75 kg
    C
    8.75 kg
    D
    9.75 kg
  • Similar Questions

    Explore conceptually related problems

    कैल्सियम कार्बाइड से पॉलिएथिलीन (पॉलिथीन) का निर्माण निम्न प्रकार होता है: CaC_(2) + 2H_(2)O to Ca(OH)_(2) + C_(2)H_(2) C_(2)H_(2) + H_(2) to C_(2)H_(4) n(C_(2)H_(4)) to (-CH(2) -CH_(2)-)_(n) 64 kg CaC_(2) से प्राप्त पॉलिएथिलीन (पॉलिथीन) का द्रव्यमान (kg में)

    From the following reaction sequence, {:(CaC_(2) + H_(2) O to CaO+ C_(2)H_(2)),(" "C_(2)H_(2)toC_(2)H_(4)),(" "nC_(2)H_(4) to (C_(2)H_(4))_(n)):} calculate the mass of polyethylene which can be produced from 10 kg of CaC_(2)

    E+F overset(Delta)underset(2000^(@)C)rarrCaC_(2) " " CaC_(2) overset (Delta)underset (N_(2))rarrD+E CaC_(2) overset(H_(2)O)rarrAuarr+B B(aq) overset(CO_(2)" gas (excess)") rarr G G overset("diluteHCl")rarrH+I uarr+H_(2)O" " H overset(Na_(2)SO_(4)) rarrJ+K [F is a crystalline solid, E is obtained in elemental from, J is percipitated out] Select correct statement

    Reaction : 2CaO+C to CaC_(2)+2CO 2CaC_(2)+ 2H_(2)O to A+B If A is involved in the neutralisation reaction with acid, then B may be

    Polythylene is obtained from calcium cabide . CaC_(2) +2H_(2)O to Ca(OH)_(2)+C_(2)H_(5) C_(2)H_(2)+H_(2) to C_(2)H_(4) nC_(2)H_(4) to (--CH_(2)-CH_(2)--)_(n) Therefore , the amount of polyethylen obtained for 64 kg CaC_(2) is