The hydrolysis of sucrose produce a mixture which is

Options

A. Laevorotatory
B. Dextrorotatory
C. Equally both (+) and (-)rotatory
D. Optically inactive

Answer

To solve the question regarding the hydrolysis of sucrose, we will follow these steps:

### Step 1: Understand the Composition of Sucrose
Sucrose is a disaccharide composed of two monosaccharides: glucose and fructose. Its chemical formula is C12H22O11.

### Step 2: Identify the Products of Hydrolysis
When sucrose undergoes hydrolysis, it breaks down into its constituent monosaccharides:
- Glucose (C6H12O6)
- Fructose (C6H12O6)

### Step 3: Determine the Optical Activity of the Products
- Glucose is dextrarotatory, meaning it rotates plane-polarized light to the right (positive rotation). Its specific rotation is +52.70°.
- Fructose is levorotatory, meaning it rotates plane-polarized light to the left (negative rotation). Its specific rotation is -92.92°.

### Step 4: Analyze the Mixture of Rotations
When these two sugars are mixed together after the hydrolysis of sucrose:
- The positive rotation from glucose and the negative rotation from fructose will partially cancel each other out.
- Since both sugars are present in equal amounts, the resultant mixture will not exhibit a net optical rotation.

### Step 5: Conclusion
The hydrolysis of sucrose produces a mixture that is optically inactive because the dextrarotatory and levorotatory contributions balance each other out.

### Final Answer
The hydrolysis of sucrose produces a mixture that is optically inactive.

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