A solution containing 34.2 g of cane-sugar `(C_(12)H_(22)O_(11))` dissolved in `500cm^(3)` of water froze at `-0.374^(@)C`. Calculate the freezing point depression constant of water.

Explanation

To solve the problem of calculating the freezing point depression constant (Kf) of water, we will follow these steps:

### Step 1: Identify the given data
- Mass of cane sugar (C₁₂H₂₂O₁₁) = 34.2 g
- Volume of water = 500 cm³
- Freezing point of the solution = -0.374 °C
- Freezing point of pure water = 0 °C

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