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At 100^(@)C the vapour pressure of a sol...

At `100^(@)C` the vapour pressure of a solution of `6.5g` of an solute in `100g` water is `732mm`.If `K_(b)=0.52`, the boiling point of this solution will be :

Text Solution

Verified by Experts

The correct Answer is:
`101.064^(@)C`
`p_(0)=760mm, p_(s)=732mm." First apply "(p_(0)-p_(s))/(p_(0))=(n_(2))/(n_(1))=(n_(2))/(1000//81)" "("taking "w_(1)=1000g)`
`n_(2)="molality (m)"`
`"Apply "DeltaT_(b)=K_(b)xxm`.
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Knowledge Check

  • At 100^(@)C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If K_(b)=0.52, the boiling point of this solution will be

    A
    `102^(@)C`
    B
    `103^(@)C`
    C
    `101^(@)C`
    D
    `100^(@)C`

  • At 100^(@)C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this soltuion will be

    A
    `101^(@)C`
    B
    `100^(@)C`
    C
    `102^(@)C`
    D
    `103^(@)C`

  • At 100^@C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If k_b = 0.52 , the boiling point of this solution will be

    A
    `102^@C`
    B
    `103^@C`
    C
    `101^@C`
    D
    `100^@C`

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