At `100^(@)C` the vapour pressure of a solution of `6.5g` of an solute in `100g` water is `732mm`.If `K_(b)=0.52`, the boiling point of this solution will be :

Answer

`101.064^(@)C`

Explanation

`p_(0)=760mm, p_(s)=732mm." First apply "(p_(0)-p_(s))/(p_(0))=(n_(2))/(n_(1))=(n_(2))/(1000//81)" "("taking "w_(1)=1000g)`
`n_(2)="molality (m)"`
`"Apply "DeltaT_(b)=K_(b)xxm`.