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Calculate the boiling point of a solutio...

Calculate the boiling point of a solution prepared by adding 15.00 g of NaCl to 250 g of water . `(K_(b) = 0.512` K kg `mol^(-1)` and molar mass of NaCl = 58.44 g `mol^(-1)`)

Text Solution

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The correct Answer is:
`101.05^(@)C`
`DeltaT_(b)=iK_(b)m=2xx0.512xx(15)/(58.44)xx(1)/(250)xx1000=1.05, T_(b)=100+1.05^(@), T_(b)=100+1.05^(@)C=101.05^(@)C`
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Calculate the boiling point of a solution prepared by adding 15.0 g of NaCl of 250.0 g of water ( K_(b) for water ="0.512 K kg mol"^(-1) , Molar mass of NaCl = 58.44 g)

(a) Define the terms osmosis and osmotic pressure. Is the osmotic pressure of a solution a colligative property? Explain. (b) Calculate the boiling point of a solution prepared by adding 15.00g of NaCl to 250.0g of water. ( K_(b) for water =0.512K kg "mol"^(-1) , Molar mass of NaCl=58.44g )

Knowledge Check

  • The elevation in boiling point of a solution of 9.43 g of MgCl_2 in 1 kg of water is ( K_b = 0.52 K kg mol^(-1) , Molar mass of MgCl_2 = 94.3 g mol^(-1) )

    A
    0.156
    B
    0.52
    C
    0.17
    D
    0.94

  • The boiling point of solution containing 68.4 g of sucrose ("molar mass" = 342 g mol^(-1)) in 100 g of water is (K_(b) "for water" = 0.512 K. kg mol^(-1))

    A
    `100.02^(@)C`
    B
    `98.98^(@)C`
    C
    `101.02^(@)C`
    D
    `100.512^(@)C`

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