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Calculate the mass of urea (NH(2)CONH(2)...

Calculate the mass of urea `(NH_(2)CONH_(2))` required in making `2.5 kg `of `0.25 `molal aqueous solution.

Text Solution

Verified by Experts

0.25 molal aqueous solution of urea means that
Moles of urea = 0.25 mole.`" "` Mass of solvent (water) = 1 kg = 1000 g
`"Molar mass of urea "(NH_(2)CONH_(2))=14+2+12+16+14+2="60 g mol"^(-1)`
`therefore" 0.25 mole of urea "="0.25 mole "xx"60 g mol"^(-1)=15g`
Thus, 1.015 kg of solution contain urea = 15 g
`therefore" 2.5 kg of solution will require urea "=(15 g)/(1.015 kg)xx2.5kg=37g.`
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Calculate the mass of urea (NH_2CONH_2) required in making 2.5 kg of 0.25 molal aqueous solution.

Calculate the mass of urea (NH_(2)CONH_(2)) required to prepare 2.5 kg of 0.25 molal aqueous solution.

Knowledge Check

  • What is the mass of urea required for making 2.5 kg of 0.25 molal aqueous solution?

    A
    37 g
    B
    25 g
    C
    125 g
    D
    27.5 g

  • Mole fraction of a solute in 2.5 molal aqueous solution is

    A
    `0.43`
    B
    `0.043`
    C
    `4.3`
    D
    `43`

  • Mole fraction of a solute in 2.5 molal aqueous solution is:

    A
    0.43
    B
    0.043
    C
    4.3
    D
    43

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