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Vapour pressures of benzene and toluene ...

Vapour pressures of benzene and toluene in a mixute at `50^(@)C` are given in mm by `P=179 X_(B)+92` where `X_(B)` is the mole fraction of benzene. Calculate.
(c) If the vapours are removed and condensed into liquid and again brought to the temperature of `50^(@)C`, what would be the mole fraction of benzene in the vapour phase?

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To solve the problem, we need to determine the mole fraction of benzene in the vapor phase after the vapors are removed and condensed back to liquid at a temperature of \(50^\circ C\). ### Step-by-Step Solution: 1. **Understand the given equation**: The vapor pressure \(P\) of the mixture at \(50^\circ C\) is given by: \[ P = 179 X_B + 92 \] ...
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Vapour pressures of benzene and toluene in a mixute at 50^(@)C are given in mm by P=179 X_(B)+92 where X_(B) is the mole fraction of benzene. Calculate. (a) Vapour pressures of pure benzene and toluene at 50^(@)C .

Vapour pressures of benzene and toluene in a mixute at 50^(@)C are given in mm by P=179 X_(B)+92 where X_(B) is the mole fraction of benzene. Calculate. (b) Vapour pressure of a liquid mixture obtained by mixing 224 g benzene and 184 g of toluene.

Knowledge Check

  • The vapour pressure of pure benzene and pure toluene at a particular temperature are 100 mm and 50 mm repectively. The mole fration of benzene in the vapour phase in contact with equimolar solution os benzene and toluene is:

    A
    0.67
    B
    0.75
    C
    0.33
    D
    0.5

  • The vapour pressures of pure benzene and toluene are 160 and 60mm Hg respectively. The mole fraction of benzene is vapour phase in contact with equimolar solution of benzene and toluene is

    A
    `0. 0 73`
    B
    `0. 0 27`
    C
    `0. 27`
    D
    `0. 73`

  • The vapour pressure of pure benzene and toluene are 160 and 60 mm Hg respectively. The mole fraction of benzene in vapour phase in contact with equimolar solution of benzene and toluene is :

    A
    0.073
    B
    0.027
    C
    0.27
    D
    0.73

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    Vapour pressure of C_(6)H_(6) and C_(7)H_(8) mixture at 50^(circ)C are given by P=179X_(B)+92 , where X_(B) is mole fraction of C_(6)H_(6) . Calculate (in mm ): (a) Vapour pressure of pure liquids. (b) Vapour pressure of liquid mixture obtained by mixing 936g C_(6)H_(6) and 736g toluene. ( c) If the vapours are removed and condensed into liquid and again brought to the temperature of 50^(circ)C , what would be mole fraction of C_(6)H_(6) in vapour state ?

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