Vapour pressures of benzene and toluene in a mixute at `50^(@)C` are given in mm by `P=179 X_(B)+92` where `X_(B)` is the mole fraction of benzene. Calculate.
(c) If the vapours are removed and condensed into liquid and again brought to the temperature of `50^(@)C`, what would be the mole fraction of benzene in the vapour phase?

Explanation

To solve the problem, we need to determine the mole fraction of benzene in the vapor phase after the vapors are removed and condensed back to liquid at a temperature of \(50^\circ C\).

### Step-by-Step Solution:

1. **Understand the given equation**: The vapor pressure \(P\) of the mixture at \(50^\circ C\) is given by:
\[ P = 179 X_B + 92 \]
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