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When mercuric iodide is added to the aqu...

When mercuric iodide is added to the aqueous solution of potassium iodide, then:

A

freezing point is raised

B

freezing point is lowered

C

freezing point does not change

D

boiling point does not change

Text Solution

Verified by Experts

The correct Answer is:
A
KI reacts with `HgI_(2)` to form a complex as
`2KI+HgI_(2)rarrK_(2)[HgI_(4)]overset("ionizes")rarr`
`underset("4 ions")ubrace(2K^(+)+2I^(-))" "underset("3 ions")ubrace(2K^(+)+HgI_(4)^(2-))`
Thus, number of ions decreases in the solution. Hence depression in freezing point is less, i.e., actual freezing point is raised.
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What will happen to the freezing point of a solution when mercuric iodide is added to an aqueous solution of potassium iodide ?

Statement-I: When mercuric iodide(s) is added to the aqueous solution of KI , the freezing point is raised. Because Statement-II: HgI_(2) reacts with KI forming complex ion [Hg]_(4)^(2-)

Knowledge Check

  • When mercuric iodide in added to the aqueous solution of potassium iodode

    A
    freezing point is lowered
    B
    freezing point is raised
    C
    boiling point is lowered
    D
    both (2) and (3)

  • When mercuric iodide is added to aqueous KI solution:

    A
    freezing point is raised
    B
    osmotic pressure is raised
    C
    boiling point is elevated
    D
    vapour pressure is raised

  • When mercuric iodide is added to an aqueous solution of Kl the

    A
    Boiling point increases
    B
    Boiling point decreases
    C
    Freezing point decreases
    D
    Osmotic pressure increases

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