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The decomposition of hydrocarbon follow...

The decomposition of hydrocarbon follows the equation `k=(4.5xx10^(11)s^(-1))e^(-28000K//T)`
Calculate `E_(a)`.

Text Solution

Verified by Experts

According to Arrhenius equation, `k="A e"^(-E_(a)//"RT")`
`:.-(E_(a))/(RT)=-(28000" K")/(T)" or "E_(a)=28000" K"xx" R"=28000" K"xx8.314" JK"^(-1)" mol"^(-1)=232.79" kJ mol"^(-1).`
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Knowledge Check

  • The decomposition of N_(2)O into N_(2) and O in the presence of gaseous argon follows second kinetics with k=(5.0xx10^(11) L "mol"^(-1) s^(-1))e^(-29000 K//T) The energy of activation is

    A
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    B
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    C
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    D
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    B
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  • The rate constant for a second order reaction is given by k=(5 times 10^11)e^(-29000k//T) . The value of E_a will be:

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    C
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