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In the reaction aA+bB to products, if co...

In the reaction `aA+bB to` products, if concentration of A is doubled (keeping B constant) the initial rate becomes four times and if B is doubled (keeping A constant), the rate becomes double. What is the rate law equation and order of reaction ?

Text Solution

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Rate `=k[A]^(2)[B]," order "=2+1=3`
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Knowledge Check

  • In the reaction of aA + B + C rarr Products, i. If concentration of A is doubled, keeping conc. of B and C constant, the rate of reaction becomes double. ii. If concentration of B is halved keeping conc. of A and C constant, the rate of reaction remains unaffected. iii. If concentration of C is made 1.5 times, the rate of reaction becomes 2.25 times. The order of reaction is

    A
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    B
    2.5
    C
    3
    D
    3.5
  • In the reaction A + B rarr Products, keeping [A] constant if [B] is doubled , the rate becomes double and keeping [B] constant if [A] is doubled , the rate becomes four times. The order of reaction is :

    A
    1
    B
    2
    C
    3
    D
    4
  • For the reaction : aA+bB to Product (dx)/(dt)=k[A]^(a)[B]^(b) If concentration of A is doubled, rate becomes four times. If concentration of B is made four times, rate becomes doubled . Hence

    A
    `-(d[A])/(dt)=-(d[B])/(dt)`
    B
    `-(d[A])/(dt)=-4(d[B])/(dt)`
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    `-4(d[A])/(dt)=-(d[B])/(dt)`
    D
    None of these
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