In acidic medium, the rate of reaction b...

In acidic medium, the rate of reaction between `[BrO_(3)^(-)]and Br^(-)` ions is given by the expression `-(d[BrO_(3)^(-)])/(dt)=k[BrO_(3)^(-)][Br^(-)][H^(+)]^(2)` It means

Rate constant of the reaction depends upon the concentration of `H^(+)` ions.

Rate of reaction is independent of the concentration of the acid added.

The change in pH of the solution will affect the rate of reaction.

Doubling the concentration of `H^(+)` ions will increase the reaction rate by 4 times.

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The correct Answer is:

C, D

Is wrong because rate constant at constant temperature, (b) is wrong because rate depends upon `[H^+]^2`, (c ) is correct be4cause change in pH mense change in `[H^+]^2`, (d) is correct because rate `prop [H^+]^2`.

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In acidic medium the rate of reaction between [BrO_(3)^(-)] and [Br^(-)] ions given by the expression - (d[BrO_(3)^(-)])/(dt) = k [BrO_(3)^(-)][Br^(-)][H^(+)]^(2) It means (i) rate of constant of the reaction depends upon the concentration of H^(+) ions (ii) rate of reaction is independent of the concentration of acid added (iii) the change in pH of the solution will affect the rate of reaction (iv) doubling the concentration of H^(+) ions will increase the reactions rate by 4 items.

only (ii)

only (iii)

only (i) and (ii)

only (iii) and (iv)

In acidic inedium the rate of reaction between BrO_(3)^(-) and Br^(-) ions is given by the expression, -(d[BrO_^(3)^(-)])/(dt)=k[BrO_(3)^(-)][Br^(-)][H^(+)]^(2) It means

rate constant of overall reaction is 4 `"sec"^(-1)`

rate of reaction is independent of the conc. of acid

the change in pH of the solution will not affect the rate

doubling the conc. of `H^(+)` ions willincrease the reaction rate by 4 times.

In acidic medium, the rate of reaction between BrO_(3)^(ɵ) and Br^(ɵ) is given by the expresison (-d[BrO_(3)^(ɵ)])/(dt) =k[BrO_(3)^(ɵ)][Br^(ɵ)][H^(o+)]^(2)

The rate constant of the reaction depends upon the concentration of `H^(o+)` ions.

The rate of reaction is independent of the concentration of the acid added.

Doubling the concentration of `H^(o+)` ions will increase the reaction rate by `4` times

The change in `pH` of the solution will affect the rate of reaction.

In acidic medium, the rate of reaction between `[BrO_(3)^(-)]and Br^(-)` ions is given by the expression `-(d[BrO_(3)^(-)])/(dt)=k[BrO_(3)^(-)][Br^(-)][H^(+)]^(2)` It means

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In acidic inedium the rate of reaction between BrO_(3)^(-) and Br^(-) ions is given by the expression, -(d[BrO_^(3)^(-)])/(dt)=k[BrO_(3)^(-)][Br^(-)][H^(+)]^(2) It means

In acidic medium, the rate of reaction between BrO_(3)^(ɵ) and Br^(ɵ) is given by the expresison (-d[BrO_(3)^(ɵ)])/(dt) =k[BrO_(3)^(ɵ)][Br^(ɵ)][H^(o+)]^(2)

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