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Explain the following : (a) CO is ...

Explain the following :
(a) CO is a better reducing agent below 983 K whereas C is a better reducing agent above 983 K
(b)Generally sulphide ores are converted into oxides before reduction
(c ) Silica is added to the sulphide ore of copper in the reverberatory furnace
(d) Carbon and hydrogen are not used as reucing agents at high temperatures.
(e) Vapour phase refining method is used for the purification of Ti.

Text Solution

Verified by Experts

(c ) Sulphide ore of copper contains iron as impurity. Silica is added to remove this impurity as iron silicate (slag).
` " " underset ("Impurity")(FeO) + SiO _ 2 to underset ("Iron silicate (slag)")(FeSiO_3) `
(d) The reason being that carbo and hydrogen react with metals at high temperature forming their carbides and hybrides respectively.
(e) Ti reacts with iodine at 523 K to form volatile ` TiI_4 ` which decomposes at high temperature (1700 K ) to form pure titanium.
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Explain the following (a) CO_(2) is a better reducing agent below 710 K whereas CO is a better reducing agent above 710 K . (b) Generally sulphide ores are converted into oxides before reduction. ( c) Silica is added to the sulphide ore of copper in the reverberatory furnance. (d) Carbon and hydrogen are not used as reducing agents at high temperature. (e) Vapour phase refining method is used for the purification of Ti

Why are sulphide ores converted to oxide before reduction?

Knowledge Check

  • Which of the following halogen acid is better reducing agent ?

    A
    HCl
    B
    HBr
    C
    HI
    D
    HF
  • A sulphide ore is first converted into its oxide before reduction. This is done because :

    A
    a sulphide ore cannot be reduced to metal at all
    B
    no reducing agent is found suitable for reducing a sulphide ore
    C
    the enthalpy of formation of `CO_(2)` is more than that of `CS_(2)`
    D
    a metal oxide is generally less stable than the metal sulphide
  • A sulphide ore is first converted into its oxide before reduction. This is done because :

    A
    a sulphide ore cannot be reduced to metal at all
    B
    no reducing agent is found suitable for reducing a sulphide ore
    C
    the enthalpy of formation of `CO_(2)` is more than that of `CS_(2)`
    D
    a metal oxide is generally less stable than the metal sulphide
  • Similar Questions

    Explore conceptually related problems

    Why are sulphide ores converted to oxide before reduction?

    CO is used as a reducing agent .

    Why are sulphide ores converted to oxide form before reduction to metal ?

    Out of C and CO which is a better reducing agent at 983K ?

    Which is better reducing agent at 983 K, C or CO ?