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Both O(2) and F(2) stabilize high oxidat...

Both `O_(2) and F_(2)` stabilize high oxidation states but the ability of oxygen to stabilize the higher oxidation state exceeds than that of flrorine. Account for this observation.

Text Solution

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Compounds in the higher oxidation states are more covalent than in lower oxidation states. Since `O^(2-)` ion has larger ionic size (140 pm) than `F^(-)` ion (136 pm), therefore, any element in a higher oxidation state can polarize `O^(2-)` ion more easily than `F^(-)` ion. As a result, oxides are more covalent than fluorides in the higher oxidation states and hence more stable than fluorides.
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How would you account for the following : (i) H_(2)S is acidic than H_(2)O . (ii) The N-O bond in NO_(2)^(-) is shorter than the N-O bond in NO_(3)^(-) . (iii) Both O_(2) and F_(2) stabilize high oxidation states but the ability of oxygen to stabilize the higher oxidation state exceeds that of florine.

How would you account for the following: Both O_2 and F_2 stabilise high oxidation states but the ability of oxygen to stabilise the higher oxidation state exceeds that of fluorine.

Knowledge Check

  • Oxygen stablises higher oxidation state because

    A
    It is electronegative
    B
    Of its tendency to form double bond
    C
    Of small size
    D
    Of large size
  • Oxygen cannot exhibit higher oxidation states due to

    A
    small size
    B
    more electronegativity
    C
    less density
    D
    lack of vacent d orbitals
  • The ability of fluorine to stabilize the highest oxidation state due to higher lattice energy can be seen in:

    A
    `CoF_(3)`
    B
    `VF_(3)`
    C
    `CrF_(6)`
    D
    All of these
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    Although fluorine is more electronegative than oxygen, but the ability of oxygen to stabilise higher oxidation states exceeds that of fluorine. Why ?

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