Home
Class 12
CHEMISTRY
Match the compounds given in Column I wi...

Match the compounds given in Column I with the oxidation state of cobalt present in it (given in Column II) and assign the correct code.
`{:(,"Column I (Compound)",,"Column I (Oxidation state of Co)"),("A".,[Co(NCS)(NH_(3))_(5)](SO_(3)),1.,+4),("B".,[Co(NH_(3))_(4)Cl_(2)]SO_(4),2.,0),("C".,Na_(4)[Co(S_(2)O_(3))_(3)],3.,+1),("D".,[Co_(2)(CO)_(8)],4.,+2),(,,5.,+3):}`

A

`{:("A (1)","B (2)","C (4)","D (5)"):}`

B

`{:("A (4)","B (3)","C (2)","D (1)"):}`

C

`{:("A (5)","B (1)","C (4)","D (2)"):}`

D

`{:("A (4)","B (1)","C (2)","D (3)"):}`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of matching the compounds with the oxidation states of cobalt, we will analyze each compound in Column I and determine the oxidation state of cobalt in each case. ### Step-by-Step Solution: **Step 1: Analyze Compound A - [Co(NCS)(NH3)5](SO3)** - Ligands: NCS (−1 charge), NH3 (neutral, 0 charge), SO3 (−2 charge). - Let the oxidation state of cobalt be \( x \). - The equation for the charge balance is: \[ x - 1 + 0 - 2 = 0 \] - Simplifying gives: \[ x - 3 = 0 \implies x = +3 \] **Step 2: Analyze Compound B - [Co(NH3)4Cl2]SO4** - Ligands: NH3 (neutral, 0 charge), Cl (−1 charge), SO4 (−2 charge). - Let the oxidation state of cobalt be \( x \). - The equation for the charge balance is: \[ x + 0 - 1 \times 2 - 2 = 0 \] - Simplifying gives: \[ x - 2 - 2 = 0 \implies x = +4 \] **Step 3: Analyze Compound C - Na4[Co(S2O3)3]** - Ligands: Na (each +1 charge, total +4 for 4 Na), S2O3 (−2 charge). - Let the oxidation state of cobalt be \( x \). - The equation for the charge balance is: \[ 4 + x - 2 \times 3 = 0 \] - Simplifying gives: \[ 4 + x - 6 = 0 \implies x = +2 \] **Step 4: Analyze Compound D - [Co2(CO)8]** - Ligands: CO (neutral, 0 charge). - Let the oxidation state of cobalt be \( x \). - The equation for the charge balance is: \[ 2x + 0 = 0 \] - Simplifying gives: \[ 2x = 0 \implies x = 0 \] ### Summary of Findings: - **Compound A**: Oxidation state of Co = +3 - **Compound B**: Oxidation state of Co = +4 - **Compound C**: Oxidation state of Co = +2 - **Compound D**: Oxidation state of Co = 0 ### Matching with Column II: - A matches with +3 (5) - B matches with +4 (1) - C matches with +2 (4) - D matches with 0 (2) ### Final Code Assignment: - A - 5 - B - 1 - C - 4 - D - 2 Thus, the correct option is **3**.

To solve the problem of matching the compounds with the oxidation states of cobalt, we will analyze each compound in Column I and determine the oxidation state of cobalt in each case. ### Step-by-Step Solution: **Step 1: Analyze Compound A - [Co(NCS)(NH3)5](SO3)** - Ligands: NCS (−1 charge), NH3 (neutral, 0 charge), SO3 (−2 charge). - Let the oxidation state of cobalt be \( x \). - The equation for the charge balance is: ...
Promotional Banner

Topper's Solved these Questions

  • CORDINATION COMPOUNDS

    PRADEEP|Exercise Assertion And Reason Types Question|5 Videos
  • CORDINATION COMPOUNDS

    PRADEEP|Exercise Long Answer Questions|7 Videos
  • CORDINATION COMPOUNDS

    PRADEEP|Exercise Short Answer Questions|64 Videos
  • CHEMISTRY IN EVERYDAY LIFE

    PRADEEP|Exercise IMPORTANT QUESTION FOR BOARD EXAMINATION|30 Videos
  • D- AND F-BLOCK ELEMENTS

    PRADEEP|Exercise IMPORTANT QUESTIONS|30 Videos

Similar Questions

Explore conceptually related problems

Match the compounds given In column I with oxidation state of cabalt present in it (given in column II) and assign the correct code.

The oxidation state of Co in [Co(NH_(3))_(5)(NO_(2))]Cl_(2)

[Co(NH_(3))_(4)(SCN)_(2)]^(+)" and "[Co(NH_(3))_(4)(NCS)_(2)]^(+) are :

Match the compounds given in column I with oxidation states of carbon given in column II and mark the appropriate choice. {:(,"Column I",,"Column II"),("(A)",C_(6)H_(12)O_(6)," (i)"," +3"),("(B)",CHCl_(3)," (ii)"," -3"),("(C)",CH_(3)CH_(3)," (iii)"," +2"),("(D)",(CO OH)_(2)," (iv)"," 0"):}